Family dentist La Grange KY

Visiting a family dentistry is a very beneficial thing. A single place where the whole family can get dental services and get rid of their dental issues easily. A family dentist will help to deal with all the dental issues and also figure out what kind of family dental issues the whole family is suffering from and what could be the reasons behind it. One should consult a family dentist from time to time.

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Ten Day Btc – Tendaybtc.com

I am not the admin or the owner of the project.
The project has paid a listing in our monitor:

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Plans:
12% Daily For 10 Days

Min. deposit:
0.001 BTC

Min. withdrawal:

Payout type:
Automatic

Affiliate program:
10%

Payment systems:
ONLY Bitcoin

Deposit and withdrawal proof:
Deposit: https://www.blockchain.com/btc/tx/dfa3838a4…bf0432773965de3
withdrawal : https://www.blockchain.com/btc/tx/69c71a5c6…8e3a3124792f8a3

Script:
undefined

Hosting:
OWL PROTECT LLC

IP-address:
91.235.142.240(Ukraine / Kyiv)
IP not used in other projects

NS servers:
ns11.v-sys.org, ns12.v-sys.org

SSL:
Free SSL valid from 15 Aug, 2020 to 14 Nov, 2020 – cPanel, Inc.

Start: Jun 03, 2020

DOMAIN INFORMATION
Registrar: Ukrnames
Period: Aug 15, 2020 – Aug 15, 2021
Registered for 1 years

This topic was created for the purpose of information.
We are not responsible for your decisions!

Register link:
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Video:
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Move One Step Ahead In Business With Cashless Payment – Payment processors

Cashless payment is a term that has created buzz across the world. As every business is going cashless, why lag behind? Make your business cashless and accept payments online easily. Setup online payment processing with simple steps and let your business expand.

Read more: https://www.paycron.com

 

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Ritrexcapital.com – HYIPs – TopGoldForum

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java – How to parse a text file that is formatted like a gradebook?

I’m trying to read a text file that has data formatted as follows:

Name|Test1|Test2|Test3|Test4|Test5|Test6|Test7|Test8|Test9|Test10   
John Smith|82|89|90|78|89|96|75|88|90|96
Jane Doe|90|92|93|90|89|84|97|91|87|91
Joseph Cruz|68|74|78|81|79|86|80|81|82|87

My goal is to be able to get each student’s average test score, as well as the average score per test (column) and the average score overall. I am having trouble “separating” the first columns (the names of the students) from their test scores. Is there a way to ignore or skip the first column? Also, what is the best way to store those test scores so that I will be able to do those calculations I mentioned?

I have successfully read the contents of the file by using the below method:

in.useDelimiter("\|");
for(int i = 0; in.hasNextLine(); i++){
    System.out.println(in.next());}

sharepoint online – How to get the Members of a Security Group via API

A customer of ours has their Sharepoint Online access permissions configured via (non-azure) security groups.

We query the roles attached to an item in Sharepoint via the Sharepoint REST API with the following request:

https://<tenant>.sharepoint.com/sites/TestSite/_api/web/RoleAssignments?$expand=Member/Users

And the response looks something like this:

{
    "odata.metadata": "https://<tenant>.sharepoint.com/sites/TestSite/_api/$metadata#SP.ApiData.RoleAssignments",
    "value": (
        {
            "odata.type": "SP.RoleAssignment",
            "odata.id": "https://<tenant>.sharepoint.com/sites/TestSite/_api/Web/RoleAssignments/GetByPrincipalId(3)",
            "odata.editLink": "Web/RoleAssignments/GetByPrincipalId(3)",
            "Member@odata.navigationLinkUrl": "Web/RoleAssignments/GetByPrincipalId(3)/Member",
            "Member": {
                "odata.type": "SP.Group",
                "odata.id": "https://<tenant>.sharepoint.com/sites/TestSite/_api/Web/RoleAssignments/GetByPrincipalId(3)/Member",
                "odata.editLink": "Web/RoleAssignments/GetByPrincipalId(3)/Member",
                "Users@odata.navigationLinkUrl": "Web/RoleAssignments/GetByPrincipalId(3)/Member/Users",
                "Users": (
                    {
                        "odata.type": "SP.User",
                        "odata.id": "https://intrafindtest.sharepoint.com/sites/TestSite/_api/Web/GetUserById(8)",
                        "odata.editLink": "Web/GetUserById(8)",
                        "Id": 8,
                        "IsHiddenInUI": true,
                        "LoginName": "c:0o.c|federateddirectoryclaimprovider|<some hexadecimal ID>_o",
                        "Title": "Besitzer von TestSite",
                        "PrincipalType": 4,
                        "Email": "TestSite@intrafindtest.onmicrosoft.com",
                        "Expiration": "",
                        "IsEmailAuthenticationGuestUser": false,
                        "IsShareByEmailGuestUser": false,
                        "IsSiteAdmin": true,
                        "UserId": null,
                        "UserPrincipalName": null
                    }
                ),
                "Id": 3,
                "IsHiddenInUI": false,
                "LoginName": "TestSite Owners",
                "Title": "TestSite Owners",
                "PrincipalType": 8,
                "AllowMembersEditMembership": false,
                "AllowRequestToJoinLeave": false,
                "AutoAcceptRequestToJoinLeave": false,
                "Description": null,
                "OnlyAllowMembersViewMembership": false,
                "OwnerTitle": "TestSite Owners",
                "RequestToJoinLeaveEmailSetting": ""
            },
            "PrincipalId": 3
        }
    )
}

Now, according to the microsoft documentation, PrincipalType 4 means that the “user” really is a “SecurityGroup”.
In our test system, the security group has an Azure ID which makes it relatively easy to get information on via the Graph API. But in our customer’s system the ID is some 16 digit hexadecimal string in a format that I can’t find anywhere else.

How can I find the members of this “SecurityGroup” via any API?

oracle – “Regular Expression” to find doubled words in a string

I have a table with below structure:

create table EMPLOYEE_INFO
( e_number            NUMBER,
  e_name              VARCHAR2(50),
  e_personal_interest VARCHAR2(2000))

Some example data :

e_number  |  e_name |  e_personal_interest 
------------------------------------------
  1       |   a     |  This person likes likes to play piano piano   
  2       |   c     |  this this person likes chila chila    
  3       |   d     |  person apears apears to be 10 years old    
  4       |   c     |  she is is 10 years old old    

As you can see in e_personal_interest column of the table , some words are repeated twice (for instance for the first record we have ‘piano piano’), what I want to do is to find those records that have this problem . I used powerful Regular Expression and what I’ve written so far is below query :

select t.e_number,
       t.e_name,
       regexp_substr(t.e_personal_interest,
                     '(^|((:space:)(:punct:))+)(((:alpha:))+)' ||
                     '((:space:)(:punct:))+2' ||
                     '($|((:space:)(:punct:))+)') doubled_word
  from employee_info t
 where regexp_like(e_personal_interest,
                   '(^|((:space:)(:punct:))+)(((:alpha:))+)' ||
                   '((:space:)(:punct:))+2' || '($|((:space:)(:punct:))+)');

The problem with above query is that it just shows the first set of words that are repeated after each other for example it just shows “this this” for the second record . I want to have all sets of words that are repeated after each other for all records, "this this" and also "chila chila" for the second record for instance.

I was wondering if you could help me with this.
thanks in advance.