Let $0 = t_0 < t_1 < t_2 < cdots < t_N = 2 pi$.

I compute the points on the closed curve $F(t)$ in the complex plane , (Set $epsilon = +infty$) :

$$P_i = F(t_i)$$

$$P_{i+1} = F(t_{i+1})$$

if $|P_i – P_{i+1}| < epsilon$: then set $epsilon := |P_i – P_{i+1}|$.

In the next step I consider circles around those points on the curve of radius $epsilon/2$

Let $L = {}$

for $i,j$ in $0,1,2,…,N, i neq j$:

if $| P_i – P_j | < epsilon$: then add $Q = (P_i+P_j)/2$ to the list of intersection points $L$

This method seems to approximately work on some curves if $N$ is a large number:

Example (Please wait a few seconds for the plot to show up.)

Q1) Is it possible to prove, that this method will always find the intersection points if $N$ goes to infinity?

Q2) What better way would you suggest in the second step when testing if the circles overlap, instead of iterating $Ncdot (N+1)/2$ times over the points?

Thanks for your help!