Any way to use Set and/or SetDelayed to index a set of Fit functions?

I was a bit curious if anyone knows of any compact way to use Set and/or SetDelayed if we want to, say, generate Fit functions and index them as well.

To demonstrate what I had in mind, consider the following data set for a minimal working example:

data = { {{1, 2}, {2, 4}, {3, 6}} , {{1, 1}, {2, 2}, {3, 3}} };

Now it’s apparent that fitting data((1)) and data((2)) should provide the functions f(x)=2x and f(x)=x, respectively. But I was hoping to combine Set (=) and/or SetDelayed (:=) in the simplest manner, so that I may define a single compact function that can provide both the fit functions and the numerics for each fit.

Defining

fitdata(i_, x_) := Fit(data((i)), {1, x}, x)

works at the indexing level, where I can input a value for i and evaluate fitdata(1,x) and fitdata(2,x) to return either functional dependences on x. However, trying to input a value for both i and x yields an error, and I was wondering if anyone knows the easiest way to define a function that can both return the ith Fit function AND return a number corresponding to an input x for this function.

I’m aware that there are a number of simple ways we can both index a set of Fit functions and obtain numerical values of the fit, including but not limited to:

  • storing each function into a list that may be indexed, and using a rule to pass an x argument for the desired element
  • removing the x-dependence of the function and using a rule to cast an x-value for fitdata(i_) := Fit(data((i)), {1, x}, x).

However, I’d like to avoid adding rules or defining new variables if I can, since I’m worried my code will get a bit messy or over-complicated whenever I start iterating over these functions to calculate things here or make some plots there, etc.

The function that I had in mind above would probably be the cleanest way for me to implement things, so I was just wondering if anyone knows of a way that some fit_data(i,x) can be defined to act in this manner I originally envisioned. I suspect there may be some way to use Set and/or SetDelay so that the expression is evaluated in the way that I hope, but I am not sure.

I tried looking some solutions up on the forum but most answers were a bit more complicated than the alternatives I laid out above, or they discussed memoization which doesn’t seem to be necessary in the case I’ve described here.