How to show that the quick-sort algorithm runs in $O(n^m)$ time on average for some constant $m < 2$?
Because on average, the expected running time is in $O(nlog n)$. The algorithm should not be in exponential time.
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How to show that the quick-sort algorithm runs in $O(n^m)$ time on average for some constant $m < 2$?
Because on average, the expected running time is in $O(nlog n)$. The algorithm should not be in exponential time.