# c++ – Can’t determine if two squares/rectangles are intersecting each other

As a online graphical I used: https://www.khanacademy.org/computer-programming/spin-off-of-rectx-y-width-height-radius/4975791745220608

The rectangle coordinates:

rectangle 1: x: 180 y: 30

rectangle 2: x: 160 y: 30

What I noticed is that the render begins from a point and is increased on X axis by width and Y axis by height. So i deduced the following things: x1 and y1 are equal to rectangle coordinates (x1 and y1 being the top left corner) and x2, y2 are the bottom right corner/coordinates which are equal to the sum of square coordinates or in other words x1 and y1 and the width & height of the square.

That’s the code i made:

``````#include <stdio.h>
#include <iostream>

struct A
{
int x1, x2;
int y1, y2;
};

struct B
{
int x1, x2;
int y1, y2;
};

bool doOverlap(A a, B b)
{
if (a.x1 < b.x2 && a.x2 > b.x1 &&
a.y1 > b.y2 && a.y2 < b.y1)
return true;

return false;
}

int main()
{
/*
Rectangle 1 coords: X: 180 Y: 30
Rectangle 2 coords: X: 160 Y: 30
*/

A a;
B b;

/*
The render begins from top left corner (that's our center and
from here begins the render with +width on x and +heigth on y
(correct me in case i'm wrong but that's what i noticed: https://imgur.com/a/nZKBB0m
(as can you see in that photo, the white rectangle has l1: (x,y): 0 0)

rectangles are 40x40
*/
a.x1 = 180;
a.y1 = 30;
a.x2 = a.x1 + 40;
a.y2 = a.y1 + 40;

b.x1 = 160;
b.y1 = 30;
b.x2 = b.x1 + 40;
b.y2 = b.y1 + 40;

if (doOverlap(a, b))
{
std::cout << "y";
}
else
std::cout << "n";

return 0;
}
``````

The problem is it always return false (checked a lot of codes but no one of them seems like are working)
So,what do i do wrong?