I have carried out the implicit differentiation of the original formula (x-y^3=2xy) to get the equation;
dy/dx = – (2y-1)/(3y^2-2x)
Now i need to find the equation of the tangent at point (-1, 1), i’ve plugged the values into the formula to get;
dy/dx = – 1/5
but have a suspicion i may be missing something.