# Evaluate \$y”’+3y”+3y’+y = e^{it}\$

$$y”’+3y”+3y’+y = e^{it}$$

I’ve got this method of undermined coefficients but i am unable to find the particular solution. I got the complimentary solution as $$Y_c = {C_1}{e^{it}}+ {C_2}{x}{e^{it}}+{C_3}}{x^{2}{e^{it}}$$ but keep getting the wrong answer when i try to find the particular.