functional programming – Pass an optional function as argument to a python function

I want to pass an optional function to another function in python. If no function is passed, then it should just pass over the execution of that (non-existent) function.
The below code works, but I was wondering whether that is a good way. I don’t really like that I have to define the do_nothing function.

from typing import Callable

def do_nothing():
    pass

def some_function(arg1: str, arg2: str, optional_function_to_execute: Callable=do_nothing) -> None:
    print(arg1)
    optional_function_to_execute()
    print(arg2)

def optional_1() -> None:
    print("something1")

def optional_2() -> None:
    print("something2")

some_function("test1", "test2", optional_1)
some_function("test1", "test2", optional_2)
some_function("test1", "test2")