# In triangle \$ABC\$ altitudes \$BE\$ and \$CF\$ are drawn to sides \$AC\$ and \$AB\$ respectively. Show that \$BE = CF\$ iff \$AB = AC\$.

In triangle $$ABC$$ altitudes $$BE$$ and $$CF$$ are drawn to sides $$AC$$ and $$AB$$ respectively. Show that $$BE = CF$$ iff $$AB = AC$$.

I’m unable to write figure here. I have complete a struck.