Three players A,B, and C take turns to roll a dice; they do this in the order ABCABC….

Show that the probability that the first 6 to appear is thrown by A,the second 6 to appear is thrown by B, and the third 6 to appear is thrown by C is 46656/753571.

I’m new to this problem,the best clue I could find is a similar problem which calculating the probability A throws 6 first,B second and C third,but this problem is more complicate when A could throws 6 first and cann’t throws multiple 6s until B did.I don’t know how to tackle this case.Can you suggested me the way to do this problem.much appreciated