Here is the problem:

Given a numpy array ‘a’ that contains n elements, denote by b the set

of its unique values in ascending order, denote by m the size of

array b. You need to create a numpy array with dimensions n×m , in

each row of which there must be a value of 1 in case it is equal to

the value of the given index of array b, in other places it must be 0.

```
import numpy as np
def convert(a):
b = np.unique(sorted(a))
result = ()
for i in a:
result.append((b == i) * 1)
return np.array(result)
a = np.array((1, 1, 2, 3, 2, 4, 5, 2, 3, 4, 5, 1, 1))
print(convert(a))
```

This is my solution. is there some improvments that I can make?

I’m not sure about declaring regular list to the result and then converting it into np.array.