I have implemented k means as below, and as far as I know, it doesn’t guarantee k grouping when given k. But the task I have which is https://justpaste.it/5cmte, requires me to return exactly k clusters. How should I go around that?

K means:

```
import sys, random, math
from collections import defaultdict
def pointAvg(points):
dimensions = len(points(0))
newCenter = ()
for dimension in range(dimensions):
dimSum = 0
for p in points:
dimSum += p(dimension)
newCenter.append(dimSum / float(len(points)))
return newCenter
def updateCenters(dataSet, assignments):
newMeans = defaultdict(list)
centers = ()
for assignment, point in zip(assignments, dataSet):
newMeans(assignment).append(point)
for points in newMeans.values():
centers.append(pointAvg(points))
return centers, newMeans
def assignPoints(dataPoints, centers):
assignments = ()
for point in dataPoints:
shortest = float('inf')
shortestIndex, distances = 0, 0
for i in range(len(centers)):
val = distance(point, centers(i))
distances += val
if val < shortest:
shortest = val
shortestIndex = i
assignments.append(shortestIndex)
return (assignments, distances)
def distance(a, b):
dimensions = len(a)
_sum = 0
for dimension in range(dimensions):
differenceSq = (a(dimension) - b(dimension)) ** 2
_sum += differenceSq
return math.sqrt(_sum)
def generateK(dataSet, k):
centers = ()
dimensions = len(dataSet(0))
minMax = defaultdict(int)
for point in dataSet:
for i in range(dimensions):
val = point(i)
minKey = 'min_%d' % i
maxKey = 'max_%d' % i
if minKey not in minMax or val < minMax(minKey):
minMax(minKey) = val
if maxKey not in minMax or val > minMax(maxKey):
minMax(maxKey) = val
for _k in range(k):
randPoint = ()
for i in range(dimensions):
minVal = minMax('min_%d' % i)
maxVal = minMax('max_%d' % i)
randPoint.append(random.uniform(minVal, maxVal))
centers.append(randPoint)
return centers
def kMeans(dataset, k):
kPoints = generateK(dataset, k)
assignments = assignPoints(dataset, kPoints)(0)
oldAssignments = None
while assignments != oldAssignments:
updatedCenters = updateCenters(dataset, assignments)
newCenters = updatedCenters(0)
means = updatedCenters(1)
oldAssignments = assignments
assignedPoints = assignPoints(dataset, newCenters)
assignments = assignedPoints(0)
sumDistances = assignedPoints(1)
print(sumDistances)
return (newCenters, means)
if __name__ == '__main__':
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
i, points = 0, ()
for line in sys.stdin:
line = line.rstrip()
line = line.split()
line(0), line(1) = int(line(0)), int(line(1))
if (i == 0):
n, k = line(0), line(1)
else:
points.append(line)
i += 1
clusters = kMeans(points, k)
for i in range(k):
print('%g' % clusters(0)(i)(0), '%g' % clusters(0)(i)(1), len(clusters(1)(i)), end=' ')
for j in range(len(clusters(1)(i))):
print(points.index(clusters(1)(i)(j)) + 1, end=' ')
print()
```

**Example input:**

6 3

1 2

5 5

7 3

2 4

9 9

3 6

**Output**:

10.8982

1.5 3 2 1 4

3 6 1 6

7 5.66667 3 2 3 5

Sometimes, the same input, gives k-1, k-2 clusters instead of k.

So my point is that. k means does not guarantee k clusters. I am required to return exact k clusters, how should I do that?