python – Snort doesn’t capture raw packets

I have a python code on Linux to create a raw packet:

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.IPPROTO_TCP)
s.setsockopt(socket.IPPROTO_IP, socket.IP_HDRINCL, 1)

ip_header  = b'x45x00x00x28'
ip_header += b'xabxcdx00x00'
ip_header += b'x40x06xa6xec'
ip_header += b'x0ax0ax0ax02'
ip_header += b'x0ax0ax0ax01'

tcp_header  = b'x13x97x00x50'
tcp_header += b'x00x00x00x00'
tcp_header += b'x00x00x00x00'
tcp_header += b'x50x02x71x10'
tcp_header += b'xe6x32x00x00'
tcp_header += b'GGG' # Data

packet = ip_header + tcp_header


s.sendto(packet, ('10.10.10.1', 1))

When I run Snort without any rule sudo snort it captures created packet with the code mentioned above.

Commencing packet processing (pid=11114)
12/30-16:01:53.900763 10.10.10.2:5015 -> 10.10.10.1:80
TCP TTL:64 TOS:0x0 ID:43981 IpLen:20 DgmLen:43
******S* Seq: 0x0  Ack: 0x0  Win: 0x7110  TcpLen: 20

but Snort does not capture anything when I run this command:

sudo snort -c local.rules -A console

My ‍‍‍‍‍‍local.rules contains this rule:

alert tcp any any -> any any (msg:"TCP CAPTURED"; sid:1000001;)

This rule captures all tcp packets successfully, and alert with massage TCP CAPTURED but does not capture the packet created by the above code.