c – Count the number of lines in the file

Good morning, this function counts the number of lines in a file, but has a little problem. It only counts the line if it finds n. For example, to test it, I created a text file and wrote a word to see it. If it was fine but the line was not counted, I found that it was not counted because at the end of the Word hadn't pressed Enter. So she didn't think that someone without me could say another way of counting the number. Worried to say the word?
Function code:

char numerolinhas(){
    char contar;
    int linhas=0;
    FILE *file;

    file=fopen("Frutas forca.txt","r");

    char conta;
    while((conta=fgetc(file))!=EOF){
        if(conta=='n'){
        linhas++;
        }
    }
    fclose(file);

    return linhas;

Dynamic SQL query for count data

I'm working on an application that counts the number of employees in each department.

Here is my code:

SELECT 
    count(case when (JS_TITLE = 'Accounting')then 1 end)as Accounting,
    count(case when (JS_TITLE = 'Management')then 1 end)as Management,
    count(case when(JS_TITLE = 'Marketing')then 1 end )as Marketing,
    count(case when(JS_TITLE = 'HR')then 1 end)as HR
FROM EMP
LEFT JOIN JOB_STATUS ON EMP.JS_REF = JOB_STATUS.JS_REF

The thing is, however, that the user can add a new department.

Is there a better way to make this static code more dynamic?

List View Threshold – Count the number of documents in an LVWP on a WP page WITHOUT summation

I have a Web Part for the List View of the Document Library (LVWP) on my SPO page.

Because of the threshold of 5,000 items, I had to turn off all counts in the Totals menu in the List View Editor. However, I would like to know how many documents / elements are displayed in the LVWP.

Is there any code or script that can be inserted into a wp script editor to accomplish this?

count – no values ​​- batch overflow

I currently have a query with the following entries:

current query

I want to count the total amount of (sweat_status) that goes through each DAY per MONTH, but I want to exclude any input of (sweat_status) that has a value of 4.

This is my current edition with the following script:

SELECT DAY(timestamp) as 'day', COUNT(weld_status) as 'COUNT'
FROM vw_rewelds_all
WHERE MONTH(timestamp) = MONTH(curdate())
and YEAR(timestamp) = YEAR(curdate()) 
group by DAY(timestamp);

Output with current scrip

For example, the total amount of input I have for day 19 is 51 if it is actually 46 because I have 5 inputs that have the value 4.

How can you count how many times a character appears in a string? (In JavaScript)

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real analysis – proof of the Riesz representation theorem for the space of 1 point with the count.

I'm trying to solve this question:

Give an example of a measuring room $ (X, mathfrak {M}, mu) $ for which the Riesz representation theorem extends to the case $ p = infty. $

My process:

I'm trying to mimic the evidence in Royden's fourth edition of "Real Analysis" on page 402.

My example is the space of 1 point, i.e. $ X = {x_ {0} } $ With $ mu $ the count. (taking that into account $ L ^ { infty} $ in this case is the space of all limited measurable functions $ f: X rightarrow mathbb {R} $ Which is the space of constant functions, and that $ L ^ 1 $ in this case the collection of integrable functions from $ X $ but we know that $ X $ is the space of all constant functions, all of which can be integrated.)

Proof:

Since our count is 1, we are in the case $ mu (X) < infty. $ To let $ S: L ^ { infty} (X, mu) rightarrow mathbb {R} $ be a limited linear function. Define a set function $ nu $ on the collection of measurable quantities $ mathfrak {m} $ by setting it $$ nu (E) = S ( chi_ {E}) $$ to the $ E in mathfrak {M}. $that is correctly defined $ mu (X) < infty $ and thus the characteristic function of every measurable quantity is part of it $ L ^ { infty} (X, mu). $ We claim that $ nu $ is a signed measure. we have to show that $$ nu (E) = sum_ {k = 1} ^ { infty} nu (E_ {k}) $$ and the series absolutely converges $ {E_ {k} } _ {k = 1} ^ { infty} $ be a countable disjoint collection of measurable quantities and $ E = bigcup_ {k = 1} ^ { infty} E_ {k}. $ Through the countable additivity of the measure $ mu, $ $$ mu (E) = sum_ {k = 1} ^ { infty} mu (E_ {k}) < infty. $$ therefore $$ lim_ {n rightarrow infty} sum_ {k = n + 1} ^ { infty} mu (E_ {k}) = 0. $$

Consequently, $ | nu (E) – sum_ {k = 1} ^ {n} nu (E_ {k}) | = | S ( chi_ {E}) – sum_ {k = 1} ^ {n} S ( chi_ {E_ {k}}) | = | S ( chi_ {E} – sum_ {k = 1} ^ {n} chi_ {E_ {k}}) | $

….. …..

I'm just going to mimic the evidence in the book.

My question is:

Is there anything special about my example that makes the proof easier (like in the book does the proof include finding the function? $ f in L ^ 1 $as a radon-nicodymium derivative of $ nu $ in memory of $ mu $)

What exactly does Gmail's unread inbox count for?

My GMail inbox currently has the number 30 in a red circle next to it. I would like to zero this number, but I can't figure out what it actually counts.

When I'm looking for in:inbox label:inbox is:unreadI get thousands of results. I can delete them page by page, 50 at a time, and occasionally deleting a page will delete that number by two or three, but certainly never by 50.

Is there an actual Gmail search query that I can use that gives me the exact list of emails counted by my "unread inbox indicator"?

Google Sheets – How do I count the number of non-empty cells in a row, including only the cells in a column that contain a certain value?

Here is my sample sheet:
https://docs.google.com/spreadsheets/d/1xxmTnRTaA0DPAyibbiXK00YPqhwT5NXH8kf8PtBh0jg/edit?usp=sharing

Enter the image description here

I am trying to create a formula for the "Total" column that contains the total number of non-empty cells for this row, counting only cells that are in a column that contains the value "B". (0 is not empty)

With this formula (for line 2 as an example) it is quite easy to find the sum of these columns:
=SUMIF($1:$1,"B",2:2)

However, for counting non-empty cells, I couldn't find a similarly easy way to do this. I have tried to achieve this with FILTER and COUNTIF, but I couldn't find out.