applications – Will I get charged for an iOS app that a family member already paid for, if I download normally?

Will I get charged for an iOS app that a family member already paid for, if I download normally?

Short answer is, it depends on whether the app in question has Family Sharing enabled for it by the publisher of the app.

If the price shows up, even though a family member has already paid for the app, does that mean I’ll actually get charged that price again?

You won’t get charged for the app in question if and only if the following conditions are met:

  1. You are a part of a Family under Family Sharing.

  2. A family member has already bought the app in question.

  3. The app in question has Family Sharing enabled for it by the publisher.

Or is this simply a (giant!) bug in Apple’s App Store app?

This is not a bug from Apple, it’s by design. Not every app on the App Store automatically becomes available for free to the rest of the family if at least one of the family member has bought it. It’s up to the publisher of the app whether to enable Family Sharing for their app or not.

So it would appear logical and consistent that you as a user would see the app normally along with a price tag on the purchase button (which is an expected behavior). When you attempt to buy the app by tapping on the price button and it meets the eligibility criterion for Family Sharing, you are prompted that a family member has already bought the app, and, because it has Family Sharing enabled by the publisher, you won’t be charged for it.

(P.S.: While it’s for fact that this behavior is by design, the reasoning behind logical and consistent appearance is based on my personal interpretation.)

The proof of predictability. The family of all unary, partly predictable functions

Please help to prove this statement.

"The family of all unary, partially calculable functions with fully calculable extensions is calculable."

Definitions.

1) If the function h is obtained from the calculable functions f and g and they are defined everywhere, then h is an overall function.

2) A function g is called extension of the function f (subfunction) if dome (f) ⊆ dome (g) and g (x) = f (x) for each x ∈ dome (f). Where Dom (f) is the domain of the function.

Additional information:

The family of all unary predictable functions is not predictable

Thanks in advance!

Applications – How can I run as an administrator on my Childs Phone managed by Family Link?

I have found no lack of restriction on access to a child's phone. I'm trying to do the opposite.

Old device is Samsung Galaxy A10e
New device is LG G8 ThinQ

All day I have tried to install a backup APK from the old to the new device and it keeps saying

Action not allowed
This action is disabled. To learn more, contact your organization's admin

Ok, I'm neat this admin. My lowest question, where is the button "I am God, get out of my way"?

I have noticed strange, serious limitations in Family Link, such as:

  1. I cannot purchase a subscription within a game (despite my consent). Why?
  2. If you try to log in to my child's Google Drive through an app, it crashes immediately, but if you open it directly, it works. Why?
  3. When you try to run Google Play Games, it opens, turns into a white screen, and sometimes closes. Otherwise, it just remains a blank white screen until it closes. Why?

Please help, this is very frustrating. She worked very hard to get the Play Store credits she spent on her game and at the moment it is completely reset on the new device.

Note: I tried to use LG Mobile Switch, which indicates that it is "successful", and yet not all apps are identical to the old device.

Apply for a visa with my family to visit the UK

I am a Nigerian citizen and I am applying for a visa with my spouse and my only toddler to visit the UK. I work for a shipping company in Nigeria but my salary is transferred to my bank account by my employer via a cash payment (not a transfer from the company account). We also have a registered joint company, my husband has 2 part-time jobs. We both have no travel history. We have enough money in our business and personal accounts to cover the cost of the trip for 10 days. What are our chances of rejection.

Probability – testing the null hypothesis that a sample comes from a family of binomial distributions

Let's watch $ 200 $ independent drawing from an unknown distribution $ A = {0,1,2,3,4,5 } $. The type of sample observed $ hat {P} _ {200} = ( hat {P} _ {200} (0), hat {P} _ {200} (1), hat {P} _ {200} (2) , hat {P} _ {200} (3), hat {P} _ {200} (4), hat {P} _ {200} (5)) $ is equal to $ (0.05.0.34.0.31.0.24.0.04.0.02) $ respectively.

Test the null hypothesis with type I error probability. $ epsilon = $ 0.05 that the sample comes from a distribution in $ mathcal {E} $ using the method described in Note 4.2. this tutorial from Csiszar & Shields, d. H. to calculate $ D ( hat {P} _ {200} || hat {P}) $ and check if it exceeds that $ 0.95 Quantile of the chi-square distribution with the corresponding degree of freedom.

Where $ mathcal {E} $ is the family of binomial distributions with $ n = 5 $ and $ p in (0.1) $i.e.
$$ mathcal {E} = {P: P (a) = {5 choose a} p ^ a (1-p) ^ {5-a}, a in {0,1,2,3 , 4,5 }, mathrm {for , some} , p in (0,1) }. $$

When determining $ has {P} $ I tried to take advantage of the fact that I projection $ P ^ * $ from $ Q $ to a linear family $ mathcal {L} $ satisfies the Pythagorean identity $$ D (P || Q) = D (P || P ^ *) + DD (P ^ * || Q), forall P in mathcal {L}, $$ and if $ S ( mathcal {L}) = A $ then $ mathcal {L} cap mathcal {E} _Q = {P ^ * } $, and in general, $ mathcal {L} cap mathrm {cl} ( mathcal {E} _Q) = {P ^ * } $

ag.algebraic geometry – Explicit description of a family of extensions

Suppose I have two objects (simple ones for simplicity) $ A, B $ in an abelian CY2 category. The case that is important to me is $ A, B in Coh (X) $ to the $ X $ an Abelian variety or K3 surface. Accept

$$ operatorname {dim} operatorname {Ext} ^ 1 (A, B) = k> 1 $$

and i know to have a family $ F_t $ to the $ t in mathbb {P} ^ {k-1} $ Parameterize extensions

$$ 0 to B to F_t to A to 0. $$

On the other hand, we know it $ operatorname {dim} operatorname {Ext} ^ 1 (B, A) = k $ through Serre duality. It's really hard for me to understand what the sheaes in the extensions are

$$ 0 to A to ??? to B to 0 $$
in terms of $ F_t $. In general, is there a nice formula for what these are? The foundations of families are, of course, dual projective spaces $ mathbb {P} ( operatorname {Ext} ^ 1 (A, B)) $ and $ mathbb {P} ( operatorname {Ext} ^ 1 (B, A)) $ but how do I understand the sheaves myself?

digital – Should I convert my family pictures from JPEG to PNG?

I saved many family pictures in Google Drive as JPEGs – not as JPEG 2000 – as they were originally taken.

I thought the problem with JPEGs was an artifact on sharp edges, which is not too much of a problem with landscape and family pictures, but I've been worried lately that I am progressively losing each time I open it.

Should I save each of them as a PNG (or TIFF)? Space is not an issue.