## google workspace – Is there a way to filter Gmail messages based on personal level indicator?

I use Personal Level Indicator, so when I receive a message an arrow (if the message is not sent only to me) or a double arrow (if the message is sent only to me) is shown.

Is there a way to filter email by this mechanism? It would be even more useful for me to be able to filter and thus more clearly isolate those messages sent only to me.

## Google Chrome experiments with removing indicator for encrypted websites

It was reported earlier this month by NewsBytes that the popular Chrome browser will now inform you only when you’re visiting websites using insecure protocols like HTTP, doing away with displaying a lock icon beside the URL in the address bar.

The feature is available as an experimental Chrome flag on the Chrome 93 beta version and the Chrome 94 Canary build suggesting that the feature could become publicly available soon.

NewsBytes explains that “to enable the new feature on Chrome 93 Beta and Chrome 94 Canary builds, enter chrome://flags in the address bar and press enter. In the search bar on top, search for ‘security indicators.’ From the search results, locate the ‘Omnibox Updated connection security indicators’ flag and change its status from Default to Enabled. Now, relaunch the browser for your changes to take effect.”

Google has apparently added an enterprise policy for Chrome 93 called “LockIconInAddressBarEnabled” for businesses that wish to continue displaying the HTTPS security indicator

Google believes that over 90% of websites now use the secure HTTPS protocol.

## damage – Liquid indicator locations in a MacBook Pro

damage – Liquid indicator locations in a MacBook Pro – Ask Different

## Visual Studio Quick Action Indicator

Is there a way to modify the Quick Action indicator in Visual Studio?

I use the map mode on the vertical scroll bar, which shows a gray block for spots in the code where the Quick Actions are suggested.

However, when I scroll to a section of code, I have to hunt for the teeeeeny tiiiiiny gray dots, which usually blend in with the bottom of characters in the editor.

I would like to change the size of the dots, or the color, or something, just to make them easier to find.

## macos – Is MacBook able to turn on the isight camera even the green light indicator is burned or damaged?

The light is in series with the camera, so the camera will only turn on if the circuit is unbroken.

It may be possible for the light to be broken but still pass electrical current through it.

The only real way to know is to test it. I wouldn’t advise deliberately trying to damage the light in order to turn it off.

## Hide selected cell indicator from other users

When i shared a spreadsheet, i will see that if other users click on a cell , it will be higlighted in my end. I don’t want to see this because it’s quite annoying.

Is it possible to disable the highlight from other users?

## 2013 – Change source for presence indicator

We are using SharePoint 2013 and Skype for Business.

Normally the contact details web part in SharePoint displays the Skype presence details (Online, Busy,…).

Is there any way to change this web part’s “presence source” from Skype to MS Teams?

What I have found so far all deals with creating a separate web part for it which in our case wouldn’t really be an option.

## How should Firefox 89 (Proton) fix its active tab indicator?

Which of these tabs is the active one?

The left one

I ask because I just closed the wrong one by mistake. I’ve seen others confused about this too. If you were at Mozilla, how would you fix it while keeping within Proton’s general design language?

## probability – Variance of sum of indicator random variables.

I’m reading some notes and there’s part that I’m not sure about.

Lemma 6.1. Given a sequence of random variables $$X_{1}, X_{2}, ldots, X_{n}$$, let $$X=sum_{i} X_{i} .$$ Then
$$operatorname{Var}(X)=sum_{i=1}^{n} operatorname{Var}left(X_{i}right)+sum_{i neq k} operatorname{Cov}left(X_{i}, X_{j}right)$$

When a random variable $$X$$ can be written as a sum of indicator random variable of a set of events $$mathcal{A} subset Sigma$$, that is
$$X=sum_{A in mathcal{A}} I_{A}$$
then it is possible to express the variance of $$X$$ in a simple way as a sum. We note that $$mathbb{E}left(I_{A}right)=mathbb{P}(A)$$, and that $$left(I_{A}right)^{2}=I_{A}$$ for all $$A$$, and so
$$operatorname{Var}left(I_{A}right)=mathbb{E}left(left(I_{A}right)^{2}right)-left(mathbb{E}left(I_{A}right)right)^{2}=mathbb{P}(A)-mathbb{P}(A)^{2}=mathbb{P}(A)(1-mathbb{P}(A))$$
Also, it is a simple check that
$$operatorname{Cov}left(I_{A}, I_{B}right)=mathbb{E}left(I_{A} I_{B}right)-mathbb{E}left(I_{A}right) mathbb{E}left(I_{B}right)=mathbb{P}(A cap B)-mathbb{P}(A) mathbb{P}(B)=mathbb{P}(A)(mathbb{P}(B mid A)-mathbb{P}(B))$$
Therefore by Lemma $$6.1$$ we see that
$$operatorname{Var}(X)=sum_{A in mathcal{A}} mathbb{P}(A)(1-mathbb{P}(A))+sum_{A neq B} mathbb{P}(A)(mathbb{P}(B mid A)-mathbb{P}(B))=sum_{A in mathcal{A}} mathbb{P}(A)left(sum_{B in mathcal{A}} mathbb{P}(B mid A)-mathbb{P}(B)right)$$

The last inequality, when written out, would contain terms like $$mathbb{P}(A)left( mathbb{P}(B|A) – mathbb{P}(B) – mathbb{P}(B cap A) + mathbb{P}(A)mathbb{P}(B) right)$$, so the last two summands must cancel each other out, which is only possible if $$A$$ and $$B$$ are independent. But do we know this as a fact?

I’m working with examples like the following:

For example, in a random graph, $$T$$ is the sum of the indicator random variables $$I_{{A text { is a triangle }}}$$ over $$A subset(n)$$ such that $$|A|=3 .$$ So to evaluate $$operatorname{Var}(T)$$ we can use the above sum.

## probability – Why is a family of Events independent exactly when their indicator function is also independent?

If we define an indicator function like this:

$$I_{A}:=left{begin{array}{ll}1 & text { if } A text { occurs, } \ 0 & text { else }end{array}right.$$

I want to see the proof that if this indicator function with $$I_{A_{1}}, ldots, I_{A_{n}}$$ is independent- the events
$$A_{1}, ldots, A_{n} subseteq Omega$$
are also independent.

I also know how to prove that pair-wise independence doesn’t mean “family independence” so maybe this should be incorporated in the proof?

Maybe someone could show and explain to me how this can be proven