## Integration – How do I find \$ int frac {(1 + x ^ 2) (2 + x ^ 2)} {(x cos x + sin x) ^ 4} dx \$?

I came across this integral when I was studying indefinite integrals.

So far I've had many unsuccessful attempts, including partial attempts, but I couldn't find a way to continue.

I even tried to divide the numerator and denominator by $$x ^ 4$$ give in $$int frac {(1 + x ^ {- 2}) (1 + 2x ^ {- 2})} {( cos x + { sin x via x}) ^ 4} dx$$ still unable to move forward.

I even tried cheating a bit by deriving options, still nothing.

And many more..

So the problem remains. Can someone tell me how to do it?

(Note: This is a problem from a very elementary calculus course, i.e. no contour integrals, no multivariables and the like. However, I think that a differentiation under integration would be fine. It would also be helpful if answers are one of the answers available in options ( see image). .)

## Python – I got this error with a clean binary: ValueError: Invalid literal for int () with base 2: & # 39; 01010000 01010101 01010100 01000001 & # 39;

I have developed a program to convert the contents of a binary file into readable ACII. This is my code:

``````import struct
import base64
import codecs
import re
print("************Welcome to binary dumper and binary to ASCII decoder************")
print("Please only choose BINARY CONTENT files because otherwise an error will ocurr")
filename_ext = input("Enter filname to be dumped and decoded: ")
print("n")
filename = input("Please enter the filename WITHOUT the extention: ")
print("n")
print("Printing binary data...")
print("n")
f = open(filename_ext, 'rb')
f.close()
print(content)
contenttoconvert = input("Please copy the content that was output before and paste it here: ")
resubedcontent = re.sub("b|'", "", contenttoconvert)

base64_file_bytes = str(content).encode('utf-8')

a_binary_string = int(resubedcontent, 2)

binary_values = a_binary_string.split()
#Split string on whitespace

ascii_string = ""
for binary_value in binary_values:
an_integer = float(binary_value)
#Convert to base 2 decimal integer

ascii_character = chr(an_integer)
#Convert to ASCII character

ascii_string += ascii_character
#Append character to `ascii_string`

print(ascii_string)

with open("output_" + filename, 'wb')as output:
print("n")
print("Outputing file...")
print("n")
decoded_file_data = base64.decodebytes(base64_file_bytes + padding)
output.write(codecs.encode(decoded_file_data, 'hex_codec'))
``````

The content of the file I'm reading is: 01010000 01010101 01010100 01000001
So I just remove the b of the binary and the semi-quotes added, but it always says the same thing. I hope it was clear.

## pandas – Transforms the data frame column in INT – Python 3

Hello

I have this data frame that was generated from a file (.txt):

``````    NUMERO_PROCESSO ANO_PROCESSO    TRIBUNAL
0   0010402         2018            18
1   0010758         2014            01
2   0001622         2012            08
3   0020287         2019            04
4   1001446         2018            02
5   0000795         2019            07
6   1001620         2017            02
7   0001006         2019            11
8   0100584         2017            01
9   0010339         2016            18
``````

The column & # 39; ANO_PROCESSO & # 39; is a string of how I convert the DataFrame column to INT or how I solve the following problem without the errors mentioned (generating a data frame with the rows whose YEAR_PROCESS is greater than or equal to 2018):

``````df_remove = df_contas_validas.loc((int(df_contas_validas('ANO_PROCESSO')) >= 2018))
``````

Error: can't convert the series to

``````df_remove = df_contas_validas.loc((df_contas_validas('ANO_PROCESSO') >= 2018))
``````

Error: & # 39;> = & # 39; is between instances of & # 39; str & # 39; and & # 39; int & # 39; unsupported

## c – Dereferencing invalid ** exactly like (int) – standard practice?

I tried printing the return value of a thread and found that the term double blank pointer still confuses me.
My understanding was that a void * is a pointer to any type of data that can be dereferenced with an appropriate conversion, but otherwise the "levels" of referencing are preserved as with regular typed pointers (ie you cannot expect them to be the same Value you get put in`**(int **)depth2` by dereferencing it just like once `*depth2`. ).

However, in the code (below) that I scraped together for my thread return printing, it seems that I am do not dereference a Empty pointer if I only occupy it (int). Is this a case where the address is used as a value – if so, is this the normal way to return from threads? What else am I missing?

(I'm aware that the safer way to manipulate data within the thread can be caller-level storage, but I'm fairly interested in this case and what I don't understand about the invalid pointer)

Thanks a lot!

``````#include
#include
#include

{

return (void *)42;
}

int main()
{
void *res;                                        // res is itself a void *

pthread_join(tid, &res);                          // i pass its address, so void** now
printf(" %d n", (int)res);                       // how come am i able to just use it as plain int?

return 0;
}
``````

## SQL Server 2016 – Optimize XOR search in the int list

I have a large table (TableA) with about 120 million. Records. This table contains a single primary key column (type: int).

Another large table (Table B) contains the same ID column with some other fields. There is currently no foreign key restriction or unique index defined in this table (although I definitely want to consider adding a primary key restriction here).

The main task is to determine whether one of the ID values ​​in Table A is NOT shown in Table B.

``````SELECT * FROM TableA WHERE Id NOT IN (SELECT Id FROM TableB)
``````

I have this task on our database server for about 4 minutes. Now I wondered if there was a way to improve it. As far as I know, the lists may not be orderable, BUT it is guaranteed that the ID is unique for both tables. Is there a method I can use to sort these fields first (or better still have a sorted index) and then simply compare those sorted lists, or is there another approach to this?

## Script to find all Bigint that can be converted to int fields in Postgresql performance

I want to compress a Postgresql 11 database, and my idea is to convert many Bigint data types to Int data types if and only if there is a reasonable delay in the Int data type limit, taking into account the data it contains.

So can you help me find a script to find all the Bigint that can be converted to int fields in postgresql?

## Integration – calculation period \$ T = l sqrt { frac {2m} {E}} ( frac {E} {V_0}) ^ t int_ {0} ^ {1} ds (1-s ^ { frac { 1} {t}}) ^ {- frac {1} {2}} \$

Given:

$$T = l sqrt { frac {2m} {E}} ( frac {E} {V_0}) ^ t int_ {0} ^ {1} ds (1-s ^ { frac {1} { t}}) ^ {- frac {1} {2}}$$

$$l, t, V_0> 0$$.

Have to calculate the period $$(T)$$ when $$t to 0$$

So I tried to solve in two different ways, but found different solutions.
Which is the right one and why?

first way:

$$lim_ {t to 0} l sqrt { frac {2m} {E}} ( frac {E} {V_0}) ^ t int_ {0} ^ {1} ds (1-s ^ { frac {1} {t}}) ^ {- frac {1} {2}}$$

$$= l sqrt { frac {2m} {E}} lim_ {t to 0} int_ {0} ^ {1} ds (-s ^ { frac {1} {2t}}) = – l sqrt { frac {2m} {E}} lim_ {t to 0} frac {1} {1- frac {1} {2t}} s ^ {1- frac {1} {2 t}} big | _0 ^ 1 = 0$$

second way:

$$l sqrt { frac {2m} {E}} ( frac {E} {V_0}) ^ t int_ {0} ^ {1} ds (1-s ^ { frac {1} {t} }) ^ {- frac {1} {2}} = l sqrt { frac {2m} {E}} ( frac {E} {V_0}) int_ {0} ^ {1} dk (1 -k) ^ {- frac {1} {2}} tk ^ {t-1} = l sqrt { frac {2m} {E}} ( frac {E} {V_0}) ^ tt beta (t, 0.5)$$

The substitution I made: $$k = s ^ { frac {1} {t}}$$

Finally I got:

$$lim_ {t to 0} l sqrt { frac {2m} {E}} ( frac {E} {V_0}) ^ tt beta (t, 0.5) = l sqrt { frac {2m} {E}}$$

As you can see, I received 2 different answers.

I would appreciate your findings.

## Density of \$ C ( operatorname {int} (M), mathbb {R} ^ n) \$ in \$ C (M, mathbb {R} ^ n) \$

Le $$M$$ be a compact one $$m$$-dimensional manifold with limit, composed of $$k$$ various contractible connected components. Is
$$Left{ f in C (M, mathbb {R} ^ n): f (x) neq 0 mbox {only if} x in operatorname {int} (M) right}$$
tight in $$C (M, mathbb {R} ^ n)$$ for Compact Open Topology (Compact Convergence)?

## How to judge the convergence of \$ int_ {1} ^ {+ infty} frac { frac { pi} {2} – arctan x} {x} d x \$

How to judge the convergence of $$int_ {1} ^ {+ infty} frac { frac { pi} {2} – arctan x} {x} d x$$KennI know the Abel and Dirichlet methods, but none of them work for the problem. I really don't know what to do.

## Error cannot convert dfrom double to int

al meter length en el caso 2 y 3, me hace bien la excepción, pero en el case 4 me da error aqui "v (0) = v (Imin);
v (Imin) = Aux;
"y no se cómo solucionarlo.
Paso parte del código:
double () v = new double (5);
int op;

``````for(int i=0;i<5;i++)
{

do {
System.out.print("dime cinco valores decimales: ");
}while ((v(i)<0)|| (v(i) >100));

}
System.out.println("Introduzca la operación a realizar del siguiente menú de opciones: ");
System.out.println("1.-Modificar el valor almacenado en una posición: ");
System.out.println("2.-Mostrar el resultado de sumar todos los números: ");
System.out.println("3.-Mostrar el número más alto y más bajo: ");
System.out.println("4.-Situar el número más alto en la 1a posición y el más bajo en la última: ");
System.out.println("0.-Finalizar");

switch (op)
{
case 1:
int () v1;
int N;
System.out.print("dime un número del 0 al 100 ");

v1=new int(N);
for(int i=0;imax)
{
max=v(i);
imax=i;
}

}
System.out.println("máximo: "+max);

double min=Integer.MAX_VALUE;
double imin=0;
for(int i=0;i``````
``` iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii ```
``` ```
``` Author AdminPosted on March 15, 2020Categories ArticlesTags convert, dfrom, double, Error, int ```
``` Posts navigation Page 1 Page 2 … Page 15 Next page ```