Linux Fans – kindly PLEASE assist me with identifying the spam source on my Centos6.9 smtp sendmail server

The server has also httpd with PHP services running
I did read the guide here : https://a1websitepro.com/find-track-filthy-spammer-block/
I did install EXIM

My client complains they never had this happen on the Windows Server 2000, 2003, 2012 …… (yes i know Linux is better)
here are a list of commands that I have ran

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Did read and try:
https://serverfault.com/questions/647871/determine-originating-process-for-outbound-traffic

Linux Malware Detect


https://serverfault.com/questions/483650/how-to-find-which-script-on-my-server-is-sending-spam-emails

Tracing Spam from PHP Scripts


https://www.inmotionhosting.com/support/email/find-spam-script-location-with-exim/

migrating oracle to postgresql getting syntax error in at or near "RETURNING" keyword. kindly make this error free

select XMLQUERY(REPLACE(TRANSLATE(UPPER(coalesce(numstaff, 0)), ‘1ABCDEFGHIJKLMNOPQRSTUVWXYZ’, ‘1’), ‘/’, ‘ div ‘)
RETURNING CONTENT).getNumberVal() numstafftotal
, busi_hour_wd
FROM ris_shop_profile
where isshopactivated = ‘Y’;

Please help me it’s very urgent kindly give me solution 🙏

Problem 3: Reducing algorithmic bias. (35 points) You are in charge of a team of n engineers. Your team is assigned m tasks, for some m n, that need to be completed according to the following requirements:
• Each task needs to be completed by exactly one engineer, and each engineer can complete at most one task.
• For each engineer i, you are given a set Si of all the tasks that fall within his/her area of expertise. You can assign engineer i to task j only if j e LSi.
• Each engineer is labeled as either male or female. The total number of female engineers assigned to tasks must be equal to the total number of male engineers assigned to tasks.
Design an algorithm for computing an assignment of engineers to tasks, such that all the tasks are completed, if such an assignment exists. Prove that your algorithm is correct and that it runs in polynomial time (i.e. n

Hint: Use a reduction to the Circulation with Demands and Lower Bounds problem. Recall that in the Circulation with Demands and Lower Bounds problem we are given a directed graph G = (V, E) and for each e e E we are given a capacity c(e) 0 and lower bound C(e) 2 0. We are also given for every v e V some d(v) e IR, which can be either negative, zero, or positive. The goal is to compute a circulation f, that satisfies the following conditions:
• For all e e E, C(e) f (e) c(e).
• For all G V, Ee in to v f (e) ¯ e out of v f (e) — d(v).

A kindly tip

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With this in mind I am giving you all a hot tip. There are two stocks that you ought to consider getting into.

Intertape Polymer Group Inc.
World Financial Split Corp.

Check them out, invest what you can afford. I have done very well with both as of late. Good luck to you all.

how to fix the error ” invalid the type error” in the postgresql function .the code is pasted .kindly fix the code

CREATE OR REPLACE FUNCTION msaccess_utilities.choose_ (p_index bigint, p_element_1 text,
 p_element_2 text DEFAULT NULL, p_element_3 text DEFAULT NULL, p_element_4 text DEFAULT NULL,
 p_element_5 text DEFAULT NULL, p_element_6 text DEFAULT NULL, p_element_7 text DEFAULT NULL,
 p_element_8 text DEFAULT NULL, p_element_9 text DEFAULT NULL, p_element_10 text DEFAULT NULL,
 p_element_11 text DEFAULT NULL, p_element_12 text DEFAULT NULL, p_element_13 text DEFAULT NULL,
 p_element_14 text DEFAULT NULL, p_element_15 text DEFAULT NULL, p_element_16 text DEFAULT NULL,
 p_element_17 text DEFAULT NULL, p_element_18 text DEFAULT NULL, p_element_19 text DEFAULT NULL,
 p_element_20 text DEFAULT NULL) RETURNS varchar AS $body$
DECLARE

    TYPE StringCollType IS TABLE OF varchar(4000);
    v_coll StringCollType;

BEGIN
v_coll := new StringCollType();

IF p_element_1 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_1;
END IF;

IF p_element_2 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_2;
END IF;

IF p_element_3 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_3;
END IF;

IF p_element_4 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_4;
END IF;

IF p_element_5 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_5;
END IF;

IF p_element_6 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_6;
END IF;

IF p_element_7 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_7;
END IF;

IF p_element_8 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_8;
END IF;

IF p_element_9 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_9;
END IF;

IF p_element_10 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_10;
END IF;

IF p_element_11 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_11;
END IF;

IF p_element_12 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_12;
END IF;

IF p_element_13 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_13;
END IF;

IF p_element_14 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_14;
END IF;

IF p_element_15 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_15;
END IF;

IF p_element_16 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_16;
END IF;

IF p_element_17 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_17;
END IF;

IF p_element_18 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_18;
END IF;

IF p_element_19 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_19;
END IF;

IF p_element_20 IS NOT NULL THEN
  v_coll.EXTEND(1);
  v_coll(v_coll.LAST) := p_element_20;
END IF;

IF p_index < 1 OR p_index > v_coll.COUNT THEN
  RETURN NULL;
END IF;

RETURN v_coll(ROUND(p_index));
EXCEPTION
    WHEN OTHERS THEN
      RAISE EXCEPTION '%', DBMS_UTILITY.FORMAT_ERROR_STACK USING ERRCODE = '45000';
END;

$body$
LANGUAGE PLPGSQL
 STABLE;

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