How do I limit the search to a folder in Gmail?

With folder do you mean label or? When you navigate to a label, it should already fill the search bar with the required format. So if I have a label called "Finance", the search should be

label: finances and then what you are looking for

If it is nested, it is marked by a hyphen. So if I have a "Bills" folder underneath, that's the case

label: finances-bills search

tilemap – Limit height difference between neighbors on the elevation map?

I'm creating a height map with Perlin noise floor, but it needs to cover the differences between the neighboring values. A cardinal neighbor can only be -1, 0, +1 in difference, the diagonal neighbor can vary from -2 to +2, What is a good approach to making sure that the map is generated within these rules? Will Perlin or a small extension help me or should I do the second round after the card was created by Perlin or Simplex? I just do the latter by going over each tile and changing its main neighbor according to its own value, but it often goes over the same position / number.

Game Design – If an MMORPG has no limit on the number of players, will all players eventually focus on the same server?

Suppose the hardware power and network bandwidth are unlimited

You still have latency. "Bandwidth" is the transmission rate … I mean how much data can be sent and received in a given period of time.

That says nothing about how much time a given piece of data needs to reach its destination. That is, latency.

Why should there be a bad latency? Because of the network. I'll let Grace Hopper explain you nanoseconds.

Due to the poor latency in a game, the server's response takes some time to reach the clients. A. k.a. Lag. Of course, this is not the only cause for delays. Regardless, network latency causes delays.

So you can have a magic server that has infinite storage space and executes commands in virtually zero time, and the game still has a delay.

That means that regardless of the magic of the servers, it still makes sense to distribute multiple servers geographically across the world. And of course, everyone would connect with the one closest to him.


Of course, you may have multiple Magic Servers and load balancing between them, preventing all uses from being aggregated into a single server. In this case, however, no load balancing is required magically …

… except, well …

If we have a hub where millions of characters are moving … your server may be magical, but the client may not. It is a good idea to logically separate entities, if not physically, so that the client does not have to render everything. Why? Because the client's hardware is another cause of delays.

Since you have a perfect magic server, you can decide exactly what each client should see, so that clients do not have to spend time deciding to draw …

… waiting …


(This may be an open question, I'm not sure if I should ask questions here, but there does not seem to be a better place to put them, and I hope I can be inspired by discussions.)

Welcome to Worldbuilding Stack Exchange.

In a world where servers are magical, the server can render for the clients.

is there a corresponding economic, sociological and ecological model behind this?

economy

In this universe, the computing power is unlimited. That does not mean it's free. We did not say anything about the energy consumption.

I do not know if it applies in your fictitious universe, but in ours there is a maximum theoretical data density. This means that your magic servers take up an unlimited amount of physical space (I expect to grow as needed).

Likewise, we have a theoretical minimum time. The plank time. Since we can not really do anything in less than a plank time … to do more things in the same time, we need more CPUs.

sociology

In the game

If we have a conventional MMORPG, there is a chat window. Imagine the chat window with news in all the languages ​​of the world passing by at ridiculous speeds. While not separated by physical servers, it's a good idea to be able to filter by language.

There is also the problem of the masses. It's a good idea to have fewer channels to separate people. Not only because of the customer's performance, but also because large crowds can adversely affect the gaming experience.

Save game

A server that can grow indefinitely will certainly attract the attention of the authorities. What if it grows from a jurisdiction? Will different laws apply to different parts of the server?

ecology

Back to energy consumption. We do not have a growing server that could eat ecosystems … we have to feed the beast, and power plants affect the environment.

I would actually have to do the calculations – I do not take that answer seriously – to find out if you need a Type I civilization to have these servers.

See also: Matrioshka brain.


Let's face it, you do not really have the problem of having magic servers. All you need to know is that the network has latency.

Performance – 12G SAS Expander with 6G Hard Drives That Limit Speed?

I am building a server with 24 SATA III hard drives attached to a Chenbro 12G SAS expander on a 12G SAS HBA (LSI 9300) with a single SFF-8643 cable. The overall write speed is slower than hoped, and I wonder if this is due to the lack of Store & Forward technology. I can write to each disk individually at 170 Mbps, but when writing to all 24 at the same time, I get 75 Mbps or 1800 Mbps each.

According to this answer, SAS does not support S & F. Since the hard drives have 6 Gbps, I have a total of 24 Gbps between the HBA and the expander, or 2400 Mbps, and there may be another SATA translation overhead that further limits it to 1800 Mbps , With S & F support I should have 4800 Mbps for the expander.

But here is a draft proposal for SAS2 in support of S & F, which was published in 2006. I can not find more up-to-date information about it. Has S & F ever been implemented? If so, what are the benefits of buying 12G SAS hard drives instead of 6G SAS, considering that no spinning hard disk reaches nearly 6 Gbps?

http://www.t10.org/ftp/t10/document.06/06-386r0.pdf

Quote from the proposal:

Such a solution would involve data being transferred between and
Expander and target devices with 3Gb per second and data transfer
Reciprocation between expanders and 6Gbps initiator devices
second, without sacrificing connection utilization at both ends.

nt.number theory – Why can $ varepsilon $ not depend on $ A $, $ B $ and then $ ABC $ guess? But in the limit, we can choose $ Delta $, depending on $ varepsilon $?

My question is really a question, please do not vote and vote to close!

  1. After the sentence of Euler we have: if $ n $ and $ a $ So, coprime are positive integers
    $$ a ^ { varphi (n)} equiv 1 pmod {n} $$
    Equivalent if $ n $ and $ a $ Are there any Coprime-positive integers? k Are there positive integers? $$ a ^ { varphi (n)} – 1 = k.n $$,

Apply with $ n = y ^ 2 $ we have $$ a ^ { varphi (y ^ 2)} – 1 = k.y ^ 2 $$,

  1. The statement of the ABC conjecture and the definition of the limit

ABC conjecture. To the every positive real number $ varepsilon $There are only finitely many threefold $ (a, b, c) $ of coprime positive integers with $ a + b = c $, so that:
$ { displaystyle c> operatorname {rad} (abc) ^ {1+ varepsilon}.} $

See also: Define Limit:

The aspect to be grasped is that the definition requires the following conversation. You are not faced with any challenge $ varepsilon> 0 $ for a given & # 39; & # 39; f & # 39 ;, & # 39; & # 39; & # 39; & # 39; & # 39; a & # 39; & # 39; and & # 39; & # 39; L & # 39 ;. You have to answer with one $ Delta> 0 $ so that $ 0 <| x-a | < delta $ implies that $ | f (x) -L | < varepsilon $, If you can give an answer to a challenge, you have proven that the limit exists.

We can sleep in the limit $ Delta $ depend on $ varepsilon $, If in the $ ABC $ Guess we can pick $ varepsilon $ depend on $ A $. $ B $ then $ ABC $ Guess wrong. Why can not choose $ varepsilon $ depend on $ A $. $ B $ then in $ ABC $ Guess?

If the answer is yes, the current example for an ABC guess follows.

  1. Is the counterexample an ABC guess?

We choose $ a_1 $ and $ y_1 $ are coprime positive integers, so that $ a_1 <y_1 $ According to Euler's theorem we have:

$$ a_1 ^ { varphi (y_1 ^ 2)} – 1 = k.y_1 ^ 2 $$,

Now we leave $ A_1 = a_1 ^ { varphi (y_1 ^ 2)} – 1 $. $ B_1 = 1 $ in order to $ C_1 = A_1 + B_1 = a_1 ^ { varphi (y_1 ^ 2)} $,

$ Rad (A_1B_1C_1) = rad ((a_1 ^ { varphi (y_1 ^ 2)} – 1) .a_1 ^ { varphi (y_1 ^ 2)}) = rad (a_1 ^ { varphi (y_1 ^ 2)} ) .rad (a_1 ^ { varphi (y_1 ^ 2)} – 1) = $
$ rad (a_1) .rad (y_1 ^ 2. frac {a ^ { varphi (y_1 ^ 2)} – 1} {y_1 ^ 2}) le a_1.y_1.rad ( frac {a ^ { varphi (y_1 ^ 2)} – 1} {y_1 ^ 2}) le a_1.y_1. frac {a ^ { varphi (y_1 ^ 2)} – 1} {y_1 ^ 2} < frac {a_1} {y_1} .a ^ { varphi (y_1 ^ 2)} <a ^ { varphi ( y_1 ^ 2)} $,

Therefore exist $ varepsilon_1> 0 $ so that $ A_1 + B_1> Rad (A_1B_1C_1) ^ {1+ varepsilon_1} $,

  • We can also choose $ a_2 $ so that $ a_2> a_1 $, and $ A_2 = a_2 ^ { varphi (y_2 ^ 2)} – 1 $. $ B_2 = 1 $ in order to $ C_2 = A_2 + B_2 = a_2 ^ { varphi (y_2 ^ 2)} $, exist $ varepsilon_2> 0 $ so that $ A_2 + B_2> Rad (ABC) ^ {1+ varepsilon_2} $,

  • We can also choose $ a_m $ so that $ a_m> a_ {m-1} $, and $ A_m = a_m ^ { varphi (y_m ^ 2)} – 1 $. $ B_m = 1 $ in order to $ C_m = A_m + B_m = a_m ^ { varphi (y_m ^ 2)} $, exist $ varepsilon_m> 0 $ so that $ A_m + B_m> Rad (ABC) ^ {1+ varepsilon_m} $,

To let $ m longrightarrow + infty $we exist $ varepsilon $ With $ 0 < varepsilon <min ( varepsilon_1, varepsilon_2, … varepsilon_m) $, We have an infinity couple $ A, B $ so that $ gcd (A, B) = 1 $ and $ A + B> rad (ABC) ^ {1+ varepsilon} $

This implied $ varepsilon longrightarrow $ 0has infinity couple $ A, B $ so that $ gcd (A, B) = 1 $ and $ A + B> rad (ABC) ^ {1+ varepsilon} $

My question: I do not think that my proof is true. But I can not find a mistake. What's wrong with my proof above? If the proof is true, is the ABC assumption wrong?

real analysis – limit of a sequence of closed sets

To let $ K $ be a compact with empty interior $ mathbb {R} ^ {d} $ ($ d geq2 $). For all $ n = 1,2, …, $ To let $ F_ {n} $ be the dots $ x in mathbb {R} ^ {d} $ so that the (Euclidean) distance from $ x $ to $ K $ is $ leq 1 / n $, To let $ partial F_ {n} $ denote the limit of $ F_ {n} $, and $ chi_ {F_ {n}} $ be the characteristic function of $ F_ {n} $i.e. $ chi_ {F_ {n}} (x) = 1 $ if $ x in partial F_ {n} $ and $ chi_ {F_ {n}} (x) = 0 $ Otherwise.

Do we have
$$ lim_ {n to infty} chi_ {F_ {n}} = chi_ {K}? $$ ($ chi_ {K} $ is the characteristic function of $ K $)

How do I limit the connection to the port?

How do I limit the connection to the port? Web Hosting Talk

& # 39);
var sidebar_align = & right; & # 39 ;;
var content_container_margin = parseInt (& # 39; 350px & # 39;);
var sidebar_width = parseInt (& # 39; 330px & # 39;);
// ->

  1. How do I limit the connection to the port?

    Hello
    Is there a way to limit the number of connections each IP address can open to port or service?
    like limit connection to port 2082 or cpanel service … etc.


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Probability – upper limit of the expectation of the upper quantile ratio

We have a collection $ boldsymbol {S} $ from $ n $ discrete random variables $ X_1 $. $ X_2 $. $ dots $. $ X_n $ $ overset { small text {i.d.}} { small sim} $ $ mathcal {D} $, from where $ mathcal {D} $ is a distribution over $ {0, 1, ldots, U } subset mathbb {N} $ with cumulative distribution function $ F_ mathcal {D} $,

We define the sub listing that contains only the values ​​in $ boldsymbol {S} $ that's up $ Q (p) $, from where $ Q $ is the quantum function. This is:

$$
boldsymbol {S} _ { geq p} overset { smaller text {def}} {=} left {X: X in boldsymbol {S} text {and} p leq F _ { mathcal {D}} (X) right }
$$

(in words: $ X in boldsymbol {S} _ { geq p} $ if and only if it is $ p $ Population less or equal)

(below we mark $ pmb { sum} boldsymbol {C} $ as the sum of all items in the collection $ boldsymbol {C} $)

Is the following true?

$$
forall n, ;
mathbb {E} left ( frac { pmb { sum} boldsymbol {S} _ { geq p}} { pmb { sum} boldsymbol {S}} right)
le
frac { mathbb {E} pmb { sum} boldsymbol {S} _ { geq p}} { mathbb {E} pmb { sum} boldsymbol {S}}
$$

Note This is an extracted step of another question Expecting the upper quantile part.
This question is simpler and more targeted. (+ if the above statement is true, the previous question is solved)

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