## algorithms – Make two lists equal by using only few operations

This question was in one of the online judges(Chinese) and the question was as follows

“Consider you are given two $$unequal$$ $$arrays$$ $$a$$ and $$b$$ of $$integers$$ and you need to make the two arrays equal by using following operations. Select a $$integer$$ (by integer i mean both positive and negative) $$x$$ and select a $$subset$$ of $$numbers$$ from $$array$$ $$a$$ and you can $$add$$ or $$multiply$$ each $$element$$ with $$x$$ and place back them in their previous positions in $$array$$ $$a$$ . Find minimum number of operations to make $$a=b$$

It was given that $$|a|<6$$ and $$|a|=|b|$$ .

Now when $$|a|=1$$ then $$answer$$ will be $$0$$ or $$1$$.(it is simple for $$|a|=1$$)

When $$|a|=2$$ then worst case answer is $$2$$ and when they are equal answer is $$0$$ and if elements have $$common$$ $$difference$$ or $$common$$ $$factors$$ then answer is $$1$$.

But i am stuck from case $$|a|>2$$ for $$|a|=3$$ the for answer being $$0$$,$$1$$ or $$3$$ i could find ,criteria for answer being $$2$$ i have no idea and for $$|a|>3$$ i have no idea how to proceed.

Could anybody give me a hint.( only a hint, i am solving it from $$3$$ days)

Example:

$$a=(3,4,5)$$ and $$b=(10,13,16)$$ then answer is $$2$$ .first multiply whole array with $$3$$ and then add $$1$$ to whole array

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## sharepoint online – How to make copies of default lists and libraries

We are trying to copy the default Pages and Documents to another SharePoint subsite. In SharePoint online there is no option to make a template of these. In SharePoint Designer, we were able to make a template of the default Pages list, but it did not show up when creating a new App.

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## spring – Flatten nested lists and reduce the complexity in java

I’m developing a complex app with spring boot and mongodb. I have a Video class like following.(All getters setters are omitted)

``````class Video{
ObjectId _id;
private List<OReelOCategoryLGroup> listOfReelIdCategoryIdAndGroups;
//some other fields
}

public class OReelOCategoryLGroup {
ObjectId reelId;
ObjectId categoryId;
List<Group> groups;
}

public class Group {
ObjectId _id;
Boolean isMandatory=false;
String dueDate;
}
``````

From the front-end, I’m receiving a structure

``````{
"reelId":"5eda6be5b31e96f58b3a7c65",
"groupId":"5eda6bed217c01319701aea0",
"category":(
{
"categoryId":"5eda6bf48ebcb19e031f2aa2",
"videoId":("5eda6bff1230f45ae4b7e54a","5eda6c0464ba746e243a4d6d","5eda6c0eed64b31232bf1095")

},
{
"categoryId":"5eda6bf48ebcb19e031f2aa2",
"videoId":("5eda6c14214ca295b6473c78")

}
)
}
``````

The representation of the class is

``````public class OReelLCategoryOGroup {
ObjectId reelId;
ObjectId groupId;
List<OIdOVideoId> category;

}

public class OIdOVideoId {

ObjectId categoryId;
List<ObjectId> videoId;

}
``````

I want to update OReelLCategoryOGroup to each and every `videoId` what I receive from front-end. So I coded

``````public String addVideoToCurrentGroupFromAnotherReel(OReelLCategoryOGroup list) {

Set<ObjectId> notFoundIds = new HashSet<>();

for (OIdOVideoId cat : list.getCategory()) {

for (ObjectId vId : cat.getVideoId()) {
Optional<Video> video = videoRepository.findBy_id(vId);
if (video.isPresent()) {
Video v=video.get();

OReelOCategoryLGroup flat = new OReelOCategoryLGroup();

Group group = new Group();
group.set_id(list.getGroupId());
group.setIsMandatory(false);

flat.setReelId(list.getReelId());
flat.setCategoryId(cat.getCategoryId());
flat.setGroups(Arrays.asList(group));

save(v);
} else {
}

}
}

if (notFoundIds.size() > 0) {
return "Few videos successfully added to group, but " + notFoundIds.toString() + " are not found in database";
}
return "Videos successfully added to group";
}
``````

Here the complicity is O(n to the power of 2). But if `listOfReelIdCategoryIdAndGroups` contains `reelId==list.getReelId() && categoryId==cat.getCategoryId()` then I have to add the group to that list of Groups. If I’m going to check it, there will be another loop inside the nested loop. So complexicity is O(n to the power of 3).

``````for (OIdOVideoId cat : list.getCategory()) {
for (ObjectId vId : cat.getVideoId()) {
if (video.isPresent()) {

for(OReelOCategoryLGroup g:v.getListOfReelIdCategoryIdAndGroups()){
if(g.getReelId()==list.getReelId() && g.getCategoryId()==cat.getCategoryId()){
}else{
// insert
}
}
}
}
}
``````

I feel its inefficient, Is there any way to overcome to this problem with java 8, Stream APIs?

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## database – Organizing Data with Specific Group in Objects and Lists

So recently I have been working with a large-scale app that has a large number of individual objects with specific group attributes. For example, I have a list with objects such as

`{Name: "Todd", Desc: "Todd likes basketball", Team: "#23"}`

This list is has about 10k of these objects in it with about 1,000 different `obj.Team` values, ranging from `Team: #1` -> `Team: #1000`.Throughout my app, I will be using the full list of objects for certain calculations as well as just viewing all objects with a certain `obj.Team` value.

I will be using a Redux State w/ React to store these values and I was wondering what the best method would be in terms of performance, better practice, readability, etc. Would it be preferably to have two lists where one list is the full 10k objects while another list is a list of lists based on the Team value, where the same obj data is copied to two lists (with just different format)? Or would it be best to simply have a single list of these 10k objects and when I want to use some calculation on a specific `obj.Team` value, I just loop through and find the appropriate objects?

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I didn’t find my question on the forum: I want to know if I need to uncheck sites in the options / filters tab to generate adult links. Unchecked: …github….pi_blocklist_porn_all.list
Thank you

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## function construction – ReplaceAll with pattern matching not working with list of lists

When you did

``````ReplaceAll({vec1,vec2}, {x_List, c_} :> c x )
(* {{-3, 6}, {8, -20}} *)
``````

Then it took `x=vec1` and `c=vec2` which is not what you want. So it did `vec1 vec2` which is

``````vec1*vec2
(* {{-3,6},{8,-20}} *)
``````

``````(ReplaceAll(#, {x_List, c_} :> c x) &) /@ {vec1, vec2}
(*  {{4, -8}, {-3, {2, -5}}}  *)
``````

One way to find this out, is to actually insert Print statements, on the right side, like this

``````ReplaceAll({vec1, vec2}, {x_List, c_} :> (Print("x=", x, " c=", c); c x))
``````

The print does not affect the replacement, but useful to see what is being replaced. Then you would see the following In addition, if you do `Attributes(ReplaceAll)` you would see that `Listable` is not given as attribute of `ReplaceAll`

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## Need uncheck filter lists in options to porn backlinks?

I didn’t find my question on the forum: I want to know if I need to uncheck sites in the options / filters tab to generate porn links. Unchecked: https://github….pi_blocklist_porn_all.list
Thank you

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## how to revert to using global site lists to import into project

i have imported into projects by importing from clipboard into projects, how do i delete the urls it is set to post to & change it to import from global site lists.
the second part i guess is
right click on project >import target urls>from site lists
or just do the first part (whatever that is ) & let it run ?

## plotting – ListPlot and comparisons between lists

Here is an example with made up data:

``````Clear(y, z, k)
x = Range(20);
{y, z, k} = RandomInteger({-10, 10}, {3, 20});

ListPlot(
MapThread(Style({#1, #2}, If(#3 > #4, Red, Black)) &, {x, y, z, k}),
PlotRange -> All,
PlotStyle -> PointSize(0.02)
)
`````` For your second part (“Additional issue: for the first observations, the list k is empty, so I want to plot a red dot for such observations.”), you should really provide a sample of your data. Any answer would depend on its precise structure.

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## Creating a view which lists all taxnomy terms and the number they appear in a content type?

So i have a taxonomy called `Product Warnings`, and it has around 10 terms. This taxonomy is referenced in several content types (Small products, Large products, etc), and can be selected multiple times (so a user can select in the content type 1 or up to all 10 terms from the Taxonomy).

I want to create a view which lists all terms from the given taxonomy (that’s the easy part), and also count the number of times each terms is referenced in a specific content type (i.e. Small products)

So it would look like:

``````Eye damage: 44
Skin irritation: 13
Hair lose: 1
.
.
.
``````

Now, this is fairly easy to do with a `db_query` and custom code, but the trick is to do it in a view (if it’s possible)

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