google sheets – project reference number generator online

I have a construction business and a team of contractors. We are constantly faced with a problem where contractors are unsure which project reference number to assign to their projects to ensure accuracy rather than having two projects with the same number.
I was wondering if there could be a database and user input function where all the details can be entered and which will generate the next project reference. No, while also the details and the number are stored in the database.

You also wonder if the database can also be used to automatically generate the project work order form.
Can Google forms and sheets do this?
I have a subscription to wix so I can host it on my website. I also have a subscription to a cloud service.

Please recommend a solution to my problem.

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Number theory – Can we rewrite the ABC conjecture?

The ABC conjecture states that:

guess: Given, no $ ε> 0 $Then there is a constant $ C_ {ε}> 0 $ so for every triple the positive integers $ x, y, z $, satisfying $ x + y = z $ and $ gcd (x, y, z) = 1 $ we have

$$ z <C_ {ε} (rad (xyz)) ^ {1 + ε} $$

Where $ rad (xyz) $ denote the product of all divisors of $ xyz $,

To let $ D $ be the sentence of $ xyz $triple review

$$ z> rad (xyz) ^ {1 + ε} $$

This assumption is equivalent to:

guess: For each $ ε> 0 $. $ D $ has a finite number of elements

My question is: Can we rewrite the last version of the conjecture to be of the form:

guess: For each $ ε> 0 $. $ S $ has a infinitely Number of elements

Where $ S $ is another sentence dependent on $ x, y, z $ and $ ε> 0 $,

To optimize the number (*) by using only the foreign key index in PostgreSQL

I have a web app that uses a large number of data tables to connect to the database to retrieve data.
The problem is, however, that always first the total results have to be counted before the data can be paginated limit and offset

Are there any kind of special indexes or configurations that always force the calculation of the count to index only, without relying on the end table? because now it seems that it ignores the index when it asks for the count.

java – Minimum number of swaps required to bring the queue to its final state, not exceeding 2 swaps per element

Scenario or problem definition:
It is New Year and everyone is ready for the roller coaster ride in Wonderland! There are a number of people in the queue, and each person carries a sticker indicating their original position in the queue. The starting positions are increased from 1 in front of the line to n behind the line by 1.

Any person in the queue can bribe the person directly in front of them to swap positions. When two people change positions, they still wear the same sticker that marks their original positions in a line. One person can bribe at most two others. For example, if n = 8 and person bribe 5 person 4, the queue looks like this: 1,2,3,5,4,6,7,8.

Fascinated by this chaotic queue, you need to know the minimum number of bribes that have taken place to bring the queue to its current state!

operation manual
Complete the minimumBribes function in the editor below. An integer must be issued indicating the minimum number of required bribes. If the line configuration is not possible, it is too chaotic.

minimumBribes has the following parameters:

q: an array of integers

input format
The first line contains an integer, the number of test cases.

Each of the next pairs of lines is as follows: – The first line contains an integer, the number of people in the queue. The second line contains space-separated integers describing the final state of the queue.

output format
Issue an integer that specifies the minimum number of bricks required to bring the queue to its final state. Too messy if the condition is invalid, d. H. If a person must have bribed more than persons.

Sample Input

5 1 2 3 7 8 6 4
1 2 5 3 7 8 6 4

example output

Too chaotic

Basically, I'm trying to create a method that will accept the values ​​of the queue in this (final) state and return the number of bricks needed to get to the final state, starting with 1,2,3,4 , 5, … Indicate if the number of bribes per person in the queue is not more than 2. Otherwise "too messy".

The code that fails in some cases using Java streams is as follows. I want to know why I can not achieve the output with Java streams.

static void minimumBribes(int() q) {

        AtomicInteger bribeCount = new AtomicInteger(0);
        AtomicReference chaoticString = new AtomicReference();

        IntStream.rangeClosed(1, q.length).forEach(i -> {
            if (q(i - 1) > i) {
                if (q(i - 1) - i > 2) {
                    chaoticString.set("Too chaotic");
                } else {
                    bribeCount.addAndGet(q(i - 1) - i);

        if (chaoticString.get() == "Too chaotic")


The code passed without using Java streams is given below:

static void minimumBribes(int() q) {

        for (int i = 0; i < q.length; i++) {
            if (q(i) - (i + 1) > 2) {
                System.out.println("Too chaotic");

        int bribe = 0;
        for (int i = 0; i < q.length; i++) {
            for (int j = i + 1; j < q.length; j++) {
                if(q(i) > q(j)) {
                    q(j) = q(i) + q(j);
                    q(i) = q(j) - q(i);
                    q(j) = q(j) - q(i);

**Below is the complete code except for the method:**
public class MaximumTwoBribesAllowedForMovingForwardInQueue {

//Method that needs to be filled in
    static void minimumBribes(int() q) {


    private static final Scanner scanner = new Scanner(;

    public static void main(String() args) {
        int t = scanner.nextInt();

        for (int tItr = 0; tItr < t; tItr++) {
            int n = scanner.nextInt();

            int() q = new int(n);

            String() qItems = scanner.nextLine().split(" ");

            for (int i = 0; i < n; i++) {
                int qItem = Integer.parseInt(qItems(i));
                q(i) = qItem;

Can you please help us to recommend changes to achieve this with Java streams?

Example input:

5 1 2 3 7 8 6 4
1 2 5 3 7 8 6 4

Expected correct issue:
Too chaotic

Actual wrong issue:
Too chaotic