To represent more than one positive button as a CTA

We have an extension that has two different actions: yes and no. But these two actions have two different tastes. Yes for the current page and Yes for the entire domain, ie Yes for the current page. Treat this for all future pages in this domain with Yes. Similar No for the current page and No for the entire domain.

  1. I use the checkmark for yes, the cross for no and the ban for no
    for the whole domain. I'm stuck with the icon that might be the right choice for the entire site for yes.
    current symbols and their meaning

  2. Currently I show as the main CTA Yes for the current page. I want to change the behavior and make Yes Yes for the whole domain.

I plan to use a double check mark (like WhatsApp_ for Yes for the entire domain option), but I'm not sure it really conveys the meaning.

Any suggestions, how should I do that?

PS: This interface is a menu that is displayed by the browser extension

linear algebra – Show $ || A || _2 = mathrm {sup} _ {x neq 0} frac {x ^ T A x} {x ^ T x} $ where $ A $ is symmetric and positive definite

problem

Show:
$$ || A || _2 = mathrm {sup} _ {0 neq x in mathbb {R}} frac {x ^ T A x} {x ^ T x} $$
from where $ A $ : symmetrical and positive.


To attempt

Since

$$
begin {align}
|| A || _2 & = mathrm {sup} _ {0 neq x in mathbb {R}} frac {|| A x || _2} {|| x || _2} \
& = mathrm {sup} _ {0 neq x in mathbb {R}} frac {x ^ T A ^ T A x} {x ^ T x}
end
$$

I think the problem boils down to showing

$$
mathrm {sup} _ {x neq0} x ^ T A x = mathrm {sup} _ {x neq0} x ^ T A ^ T A x
$$

where I am stuck

Every help is appreciated.

Linear Algebra – Prove the relationship between the Frobenius-Perron eigenvectors of two positive matrices

To let $ A $ and $ B $ be two matrices, where $ A geq B geq 0 $, $ lambda_0 (A) $ and $ lambda_0 (B) $ represents their Frobenius-Perron eigenvalue.

The expression $ A geq B $ means that $ forall i, j, a_ {ij} geq b_ {ij} text {and} exists k, l, a_ {kl}> b_ {kl} $,

How can I prove that $ lambda_0 (A) geq lambda_0 (B) $?

Linear Algebra – Prove the relationship between the Frobenius-Perron eigenvectors of two positive matrices

To let $ A $ and $ B $ be two matrices, where $ A geq B geq 0 $, $ lambda_0 (A) $ and $ lambda_0 (B) $ represents their Frobenius-Perron eigenvalue.

The expression $ A geq B $ means that $ forall i, j, a_ {ij} geq b_ {ij} text {and} exists k, l, a_ {kl}> b_ {kl} $,

How can I prove that $ lambda_0 (A) geq lambda_0 (B) $?

What is better and why: positive action or employment with equal opportunities?

Equal opportunity.

We have had positive action for 60 years. Since that does not work, they also ask for compensation. If repairs do not work, what else do you ask?

Affirmative action is a systematic racism institutionalized against white Americans and Asian Americans. More and more Asian Americans are starting to recognize it these days and identify with Republicans on this issue. AA affects Asian Americans very much.

How is it fair that RECENT black immigrants from African countries use AA? Their ancestors never discriminated in America. It is unfair that AA's youngest black immigrants will gain an advantage if there is a qualified white / Asian American whose ancestors have lived in America for centuries, losing that chance.

AA does NOT work in a country like America, which has a high level of immigration from around the world every year.

Through positive action, unqualified persons receive positions to which they should not be entitled. You can not justify a system in which a child of an African-American millionaire (like Obama's daughters) gets access to a diversity quota in front of a poor white West Virginia miner.

,

Different result when scanning in Epson mode "color negative film" and when scanning in positive mode -> reverse curve in the post content?

Scanning removes the entire orange mask in the color negative film.

Scanning as positive and then inverting after processing will not remove it. The inversion simply changes the orange mask to a deep blue overall picture. NOT bluish, but very deep blue. Then extra work to try to remove it.

This is a difficult task in digital post-processing (not for the process, but for the result) because such extreme color shifts (to remove the strong blue) severely jeopardize digital trimming. A detail can change the colors and lose details.

The scanner can do this as analog (no digital clipping) by simply varying the scan time for each RGB color (the result acts like a correction filter in the light). Scanning color negatives is a bit slower than positive slides, but it's a very good thing.

If you do not say it's "impossible" in the digital realm, you may get an acceptable result, but it's just not the same thing. If you have the scanner, I strongly recommend using it. It is designed for the exact purpose.

These are color negatives, they are the particular problem. Positive transparencies or prints or black and white negatives do not have the orange mask. Therefore, copy methods other than scanning are not excluded (but scanners are good too).

The result of a yellowish occupation is not inherent. It will, however, be much easier to handle than the deep blue otherwise. 🙂 However, there are several factors.

Not every brand of color negative film has the same color as the orange mask, so some scanners offer a variety of film options.
Or the scanner calibration may not be accurate.

Or rather, the film may have been shot with a wrong color white balance (we only had a very small selection of films, but there was a basic choice between film type or flash type or lighting or filters). Often the recording itself needed a better white balance correction. So scan other film negatives in their different lighting situations to see how consistent the yellow cast is. Sunshine outdoors is probably more accurate than indoors.

In digital work, it would have been better if the white balance of the digital camera had been correct. Normally, however, it is rather mild and can easily be corrected in post-processing.

White balance was the same problem for film as it is today, but the lab that printed the image out of film did a good job before it was corrected for us. But it is NOT corrected in the negative yet.

Do you remember the blue flashlights? Remember, we still got a good result, whether we used it or not. The printing lab has fixed it for us. But in digital or film scans, that's our job right now.