prints – How can I glue photos back to back to a card, then laminate?

Most recommendations concerning what glues and cements are best for photographs, stem from the days of chemical-based prints. We are talking silver/gelatin black & white and dye/gelatin color prints on conventional chemical-based photo paper. These recommendations steered you away from cements with low pH and chemical content that could damage. All sound advice. Chemical-based silver/gelatin prints are attacked by sulfur, and chemical-based color prints are comprised of organic dyes that persist only if the pH is within a narrow range.

Further, both the color and the black & white images were bonded to the paper using glue made from gelatin. This is the same gelatin used to make tempting desserts. Pastes and glues that absorb moisture are no-nos; the moisture migrates to the gelatin. Add water to gelatin on paper (or film) you get a tasty meal for mold and other beasties. I think modern prints produced by inkjet and the like are more robust. Not to the point that we should throw caution the wind, but not to the point we should become paranoid as to what glue or pastes we should use.

c – Implementation of cp program that prints the number of bytes copied

I have written the code for implementation of the cp program that prints the number of bytes copied when the user presses Ctrl-C. Could someone please review this code and provide feedback. Thanks a lot.


#include<stdio.h>
#include<stdlib.h>
#include<unistd.h>
#include<fcntl.h>
#include<error.h>
#include<signal.h>
#define buffer_size 512

void signal_handler(int num);
void write_buf(int des_fd, char *buffer, size_t rlen, int *bytes);
int flag = 0;

void signal_handler(int num)
{
    printf("The caught signal number is : %dn", num);
    flag = 1;
}

void write_buf(int des_fd, char *buffer, size_t rlen, int *bytes)
{
    int wlen;

    while (1) {
        wlen = write(des_fd, buffer, rlen);
        if (wlen == -1)
            error(1, 0, "error in writing the filen");
        *bytes = *bytes + wlen;
        buffer = buffer + wlen;
        rlen = rlen - wlen;
        if (rlen == 0)
            break;
    }
}

int main()
{
    int src_fd;
    int des_fd;
    int rlen;
    int bytes;
    char buffer(buffer_size);

    signal(SIGINT, signal_handler);
    src_fd = open("src_text", O_RDONLY);
    if (src_fd == -1)
        error(1, 0, "error in opening the source-filen");
    des_fd = open("des_txt", O_WRONLY);
    while (1) {
        rlen = read(src_fd, buffer, sizeof(buffer));
        if (rlen == -1)
            error(1, 0, "error in reading the filen");
        if (rlen == 0)
            break;
        write_buf(des_fd, buffer, rlen, &bytes);
        if (flag == 1)
            printf("The number of bytes copied is :%dn", bytes);
        flag = 0;
    }
}
```

Pricing – If I have an unpublished photo of a celebrity, can I make money selling glossy prints online?

1975 was a long time ago (although I also remember the year), but this SE question is worth reading. If I read the Wikipedia page "Sheer Heart Attack" correctly, it sounds like the McFarlin Memorial Auditorium is a private indoor venue. So it might depend on whether you can reasonably expect to have permission for the photo and copyright of the work.

Catch 22 could be profitable. You don't do anything in the picture, who cares? A long time ago, right? But the general rule is that lawyers will crawl out of the woodwork the moment anything brings a significant profit. And there is every profit.

(A passing thought – this could be the reason why Rolling Stone didn't respond. Or it may be that they already have permission to publish more pictures of Freddie than they can use.)

Short answer – careful with it. A previously unseen shot of Freddie could be great news. If there is a chance that lawyers will get involved, get one first.

dnd 5e – What is the resistance of an elf in the last few prints of the Monster manual?

My copy of the Player manual and my copy of the Monster manual both state that an elf resists the following:

(…) clubs, piercing and slashing of non-magical weapons that are not silver-plated.

And then DnD Beyond (without buying books there) says:

(…) bludgeoning, piercing and slashing non-magical attacks that are not silver-plated

Meanwhile the Player manual Errata conditions:

(…) Bludgeoning, puncturing and cutting non-magical attacks that were not carried out with silver-plated weapons.

And the Monster manual Errata conditions:

Throughout the book, instances of "non-magic weapons" in damage resistance / immunity entries have been replaced with "non-magic attacks".

Applying this exact update would do my Book status:

(…) clubs, piercing and slashing of non-magical attacks that are not silver-plated.

This corresponds to the description of DnD Beyond, but "attacks that are not silver-plated" sound very wrong to me. I have no idea whether this wording is actually in the prints of the Monster manualIt is exactly what the errata say.


Which of these phrases may be correct? What is the wording in the latest prints of the Monster manual? If this wording contradicts the Player manual Errata, which one has priority?

Plot – RegionPlot3D prints an incorrect plot

I see discrepancies between plots that were used for the same region Region and RegionPlot3D,

When i use

reg4 = ImplicitRegion(
   A1 > 0 && 
    A2 > 0 && ((Mu) < -((3 Abs(A1))/2)) && ((Mu) < -(3/2) Sqrt(3)
        Abs(A2)) && (2 (Mu) + Sqrt(
       A1^2 + 16 A2^2 + 8 Abs(A1) Abs(A2)) < 0), {{A1, 0, 2}, {A2, 0, 
     2}, {(Mu), -1.5, 0}});
Region(reg4, Axes -> True, AxesLabel -> {"A1", "A2", "(Mu)"})

Enter the image description here

When i use RegionPlot3D Then I get

RegionPlot3D(
 A1 > 0 && 
  A2 > 0 && ((Mu) < -((3 Abs(A1))/2)) && ((Mu) < -(3/2) Sqrt(3)
      Abs(A2)) && (2 (Mu) + Sqrt(
     A1^2 + 16 A2^2 + 8 Abs(A1) Abs(A2)) < 0), {A1, 0, 2}, {A2, 0, 
  2}, {(Mu), -1.5, 0}, Axes -> True, 
 AxesLabel -> {"A1", "A2", "(Mu)"})

Enter the image description here

As if the surface in this figure had been smoothed, the representation is also wrong.

Why two different graphics for the same region?

html5 – Asynchronous request in vuejs prints me [object Promise] in html

This is what I tried::

{{ item }}: {{ getAccount(item) }}

  • Explanations:
  • I'm looking for something in every paragraph:
    101: box
    105: Bank checking account
    205: suppliers
  • seat.debe is a string of full IDs separated by commas
  • These IDs belong to a table called "Accounts" with the following columns: id | Surname
  • The getAccount () function sends an http request to the database and tries to get the name of the account
  • "item" effectively contains the account ID

Component getAccount () method:

async getAccount (id) {
    let response = await fetch(`/accounts/${id}`);
    let data = await response.json(); 
    let account = data.name;
    console.log(account);
    return account;
}

What I want is to print the name of the account in HTML, I use that for that console.log(account) to see the value that this variable stores. And it works, the variable account contains the account name.

The problem is that in HTML, although account contains the name of the account, it returns me:

(object Promise)

Printing – is it possible to make contact prints in the darkroom from a high-ppi phone or tablet?

Will the pixels be visible? Does the thickness of the screen glass prevent the image from being focused?

Some resin-based 3D printers work on a similar principle: an LCD monitor, which is mounted under the transparent bottom of a tank with photosensitive resin, exposes the resin and solidifies it. There is no doubt that you can create a contact print by placing your phone or tablet on a sheet of photo paper to expose it. It is unknown what quality you can expect.

You have already encountered a problem, the separation between the surface of the display and the paper caused by the glass cover of the device. However, devices vary in the thickness of this coverslip, so some may work better than others.

Another variable is the exposure time and whether you can specify that the image is only displayed after you have placed the device on the paper. If you just display the image and then place the device on the paper, it will likely become a little blurry because the device will move at the beginning and end of the exposure. If you have the technical skills, you can write a program in which the display is black and the image is shown during the exposure. Then black will appear again so that you can remove the device.

Important: Remember that you are working with a negative process here. For example, if you create a black and white print, the areas exposed to light will turn black. This means that you need a negative image to create a positive print. You could You can achieve something functional with a function on your phone that reverses the display (iOS supports this under the accessibility features). However, be aware that this feature is intended as a place to stay for a disability and may not work well for printing photos. An app created for this purpose would be a better plan.

Python – How should I name a function that prints and returns packet loss?

Functions that do multiple things are generally not a good idea.

In this case, you can ignore the returned value if you want to print the result. However, if you want to do something with the returned value, you will also need to print it, which you may not want.

A better design is to have a function that returns the value and a separate function that prints the value.