Career Problem Solution Specialist BABA JI+91-9876425548 in Bamber Bridge

Career Problem Solution Specialist BABA JI+91-9876425548 in Bamber Bridge | Web Hosting Talk


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javascript – Optimizing code solution for Palindrome Index-Hackerrank

I submitted my solution for palindrome Index coding challenge but I get “test cases terminated due to time out error”. My code is working and so I don’t know what else to do to optimize it. Please help:

function palindromeIndex(s) {
    let palindrome = s === s.split('').reverse().join('')
    if(!palindrome) {
        let i = 0
        let integerIndex = ()
        let arr = s.split('')
        while(i < s.length) {
            arr.splice(i,1)
            if(arr.join('') === arr.reverse().join('')) {
               integerIndex.push(i) 
            }
            arr = s.split('')
            i++
        }
        return integerIndex.length > 0 ? integerIndex(0) : - 1
    }else {
        return -1
    }
}

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Understanding the logic behind combinatorics and recursion solution (queries as comments in code)

Our local ninja Naruto is learning to make shadow-clones of himself and is facing a dilemma. He
only has a limited amount of energy (e) to spare that he must entirely distribute among all of his
clones. Moreover, each clone requires at least a certain amount of energy to function (m) . Your job is
to count the number of different ways he can create shadow clones.
Example:

e=7;m=2

ans = 4

The following possibilities occur:
Make 1 clone with 7 energy

Make 2 clones with 2, 5 energy

Make 2 clones with 3, 4 energy

Make 3 clones with 2, 2, 3 energy.

Note: <2, 5> is the same as <5, 2>.
Make sure the ways are not counted multiple times because of different ordering.

Answer

int count(int n, int k){
    if((n<k)||(k<1)) return 0;
    else if ((n==k)||(k==1)) return 1;
    else return count(n-1,k-1)+ count(n-k,k);   // logic behind this?
}

int main()
{
    int e,m;            // e is total energy and m is min energy per clone
    scanf("%d %d", &e, &m);
    int max_clones= e/m;
    int i,ans=0;
    for(i=1;i<=max_clones;i++){
        int available = e - ((m-1)*i);   // why is it (m-1)*i instead of m*i
        ans += count(available, i);
    }
    return 0;
}

numerics – NArgMax plotting partially wrong solution

In the following MWE, NArgMax finds the correct argmax (br1) as a function of the parameter p2 for most values of p2, but not close to zero. Instead, a vertical line is plotted. NArgMax gives a constant value to br1 for p2 close to 0.

To confirm the wrongness of the solution, in the 3D plot, the objective function to maximize is smooth and its max at different p2 reaches the origin. Thus the argmax and the maximized value should reach the origin, which can be proved theoretically as well.

No breakpoints of the Piecewise part of the objective function are where the NArgMax solution kinks to become wrong.

Clear(d1, q1, pi1, p1, p2, (Gamma), br1, pi1opt, plot1, plot3)
$Assumptions = 
  0 < q1 < q2 && 0 <= p1 < p2 && 
   0 <= p2 < q2 && (p2 - p1)*q1 >= p1*(q2 - q1) && p1 < q1 && 
   0 < (Gamma) < 1;
cdf(v_) = 
  Piecewise({{0, v < 0}, {v^2/(Gamma), 
         0 <= v < (Gamma)}, {1 - (1 - v)^2/(1 - (Gamma)), (Gamma) <= 
  v <= 1}, {1, v > 1}});
d1(p1_, p2_, q1_, q2_) = Max(0, cdf((p2 - p1)/(q2 - q1)) - cdf(p1/q1));
pi1(p1_, p2_, q1_, q2_) = p1*d1(p1, p2, q1, q2);
(Gamma) = 0.1; q1 = 1; q2 = 1.2;
br1(p2_) = br1(p2_?NumericQ) := NArgMax(pi1(p1, p2, q1, q2), p1)
{br1(0.001), br1(0.01), br1(0.1)}
pi1opt(p2_) = 
 pi1opt(p2_?NumericQ) := NMaxValue(pi1(p1, p2, q1, q2), p1)
plot1 = Plot3D({pi1(p1, p2, q1, q2)}, {p1, c1, q1}, {p2, c2, q2}, 
RegionFunction -> Function({p1, p2, z}, p1 < p2), 
AxesLabel -> {Subscript(P, 1), Subscript(P, 2)}, 
PlotStyle -> Opacity(0.5));
plot3 = ParametricPlot3D({br1(p2), p2, pi1opt(p2)}, {p2, c2, q2}, 
AxesLabel -> {Subscript(P, 1), Subscript(P, 2), Subscript((Pi), 
 1)}, PlotStyle -> {Thick, Orange, Dashed});
Show(plot1, plot3)
Plot(br1(p2), {p2, c2, q2}, AxesOrigin -> {0, 0})

How to make NArgMax find the correct maximum at all points?

Using ArgMax instead of NArgMax with the same numerical parameters, the Plot is empty and the Plot3D is missing the dotted line denoting the maximum.

A Solution To Enhance Your Forex Business

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● The company provides comprehensive solutions to all sizes of forex businesses. Whether you own a sole proprietorship forex business or your firm has more than 500 employees on its payroll, iPayTotal uses its cutting-edge technology to provide quality services to suit your payment processing needs.
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iPayTotal – A Solution To Enhance Your Forex Business – General Forex Questions & Help

jmJ8Gxb.jpg

Are you a forex broker looking for a forex merchant account to send or receive payments from your clients? Then count yourself lucky for stumbling on this post. As you may already know, operating and maintaining a forex merchant account has several risks like lack of regulation, exchange rate risk, credit risk, interest rate risk, liquidity risk, as well as leverage risk. These risks have made it different for business owners to create a merchant account. 

While there are several forex merchant account providers on the internet claiming to offer premium-quality services, one company that is like a game-charger in the industry is iPayTotal. iPayTotal knows the ins and outs of the forex market to meet the needs of every forex broker that comes their way. 

Let’s see what iPayTotal has in stock for its numerous customers.

iPayTotal is one of the leading forex merchant account providers that leverages cutting-edge technology to provide forex brokers with the best payment solutions available. The company’s goal is to help merchants set up affordable payment solutions that accept major credit/debit cards and alternative payment methods.  

iPayTotal guarantees a full-fledged payment gateway which you can add to your company’s website or any payment software you are currently using. The payment gateway prevents financial fraud and blocks any suspicious activity.  

Why Choose iPayTotal?

Here are why you should consider registering on iPayTotal:

●    The company provides comprehensive solutions to all sizes of forex businesses. Whether you own a sole proprietorship forex business or your firm has more than 500 employees on its payroll, iPayTotal uses its cutting-edge technology to provide quality services to suit your payment processing needs.
●    The forex merchant account the company will create for you can accept up to 100 currencies in more than 196 countries. 
●    You will be able to withdraw all your profits directly into your local bank account.
●    As soon as your account is approved, your starting rate is as low as 2.5% only.
●    iPayTotal complies with all known regulations for you to securely transfer your customers’ data.
●    iPayTotal uses fraud scrub technology to detect and reduce fraud attempts on the platform. You can be rest assured that your funds are safe and secure.
●    The company has a robust customer support team that will guide you through every struggle you encounter. 
●    You can track all your transaction in real-time 

iPayTotal promises to deliver top-notch services that guarantee lowest rates, flexible terms, and fast approvals. The company can help your online trading firm with payment processing needs in view of the inherent risks in the forex market. 

Are you passionate about getting started with iPayTotal? The registration process is pretty simple and straightforward. All that is required of you is to visit the iPayTotal application page and create a free account. Before your account would be approved, you would need to upload supporting documents. A list of the documents would be sent to you via email, therefore ensure you provide a valid email address. 

The company would also send you newsletters and update on their company’s services via email. Once you are able to verify your email address and upload the relevant documents, you would be one step away from enjoying affordable payment processing solutions you would ever find on the internet. 

Get all further details from: https://ipaytotal.com/forex-merchant-account/

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