How to solve the error code 0 – Everything else

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linear programming – program to solve the optimization problem

I have an optimization problem, this problem has linear constraints and non-linear constraints. I solved the linear part of MATLAB, but due to the nonlinear constraints, I could not solve it. I have downloaded barone software to solve the problem. However, this software has a number of limitations. If these restrictions are more than 10 restrictions, I have to buy the licenses and the license is expensive. Do you know a free program to solve my problem or idea?

Java – 2 classes need another class to exist first. How can I solve this circular class dependency?

In my game world Class I initialize an article rectangle in the constructor.

item1 = new Rectangle (GameRenderer.obstacle3.getX () - GameRenderer.generator2.getValue2 (), GameRenderer.generator2.getValue1 (), 5, 5);

The problem I have is initializing GameRenderer.obstacle3 on game world must already exist and create one game world, GameRenderer.obstacle3 can not be null

In other words: GameRenderer.obstacle3 but first needs GameWorld game world need GameRenderer.obstacle3 exist first

That's why I have one NullPointerException and obviously it's useless to do one Try-catch Block.

I use the rectangle for collision detection, d. H.

if (Intersector.overlaps (wizard.getBoundingRectangle (), item1)) {// getRect ()
GameRenderer.DoublePointsActive = true;
addScore (5);
}

I do not know how to solve this problem by at least restructuring myself as much as possible.

Here is a picture of what is displayed when I place a breakpoint in the appropriate codeline.

zero

Algorithms – solve T (n) = 3T (n-1) + 2

I'm trying to improve the resolution of relationship issues, so I'm making my own simple relationships and trying to solve them. I did the following repetition

T (n) = 3T (n-1) + 2 and we say that T (1) = 1

T (n) = 3 [3T(n-2) + 2] + 2
T (n) = 3 [3[3T(n-3) + 2] + 2]+ 2
T (n) = 3 [3[3[3T(n-4) + 2] + 2]+ 2]+ 2 = T (n) = 81 T (n-4) + 8
,
,
,
We say that k = n-1
T (n) = 3 ^ kT (n-k) + 2 * k
T (n) = 3 ^ k T (1) + 2 * k

I am certain how to end this and how to find out the temporal complexity in Big O.

Matrices – Can anyone help me to solve minimization?

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Sound – The microphone recording is slightly static and crackling despite all attempts to solve it

Exactly what the title says. I have a microphone that works well on Windows, but regardless of the distribution, there is always a slight click sound when using the microphone.

I tried everything and added Charge module module-hal-detect tsched = 0 to /etc/pulse/default.pa, fiddling with the language levels alsamixerYou name it, I tried it and it did not work. It crackles on, no matter what I throw.

I would be happy about any solution that you could offer.

Many Thanks.

integration – search for methods to solve: $ int_0 ^ infty frac { ln (t)} {t ^ n + 1} : dt $

Search for methods to solve the following two specific integrals:

begin {equation}
I_n = int_0 ^ infty frac { ln (t)} {t ^ n + 1} : dt qquad J_n = int_0 ^ infty frac { ln ^ 2 (t)} {t ^ n + 1} : dt
end {equation}

To the $ n in mathbb {R}, : n gt $ 1

The method I took was to take the following integral:

begin {equation}
int_0 ^ infty frac {t ^ k} {t ^ n + 1} : dt = frac {1} {n} B left (1 – frac {k + 1} {n}, frac {k + 1} {n} right)
end {equation}

From where: $ 0 leq k lt n $

Make a distinction under the curve in relation to $ k $ and the limit as $ k rightarrow 0 ^ + $ (above the dominated convergence theorem), i.

begin {align}
lim_ {k rightarrow 0+} frac {d} {dk} left[ int_0^infty frac{t^k}{t^n + 1}:dt right] & = lim_ {k rightarrow 0+} frac {d} {dk} left[frac{1}{n}Bleft(1 – frac{k + 1}{n}, frac{k + 1}{n} right) right] \
lim_ {k rightarrow 0+} int_0 ^ infty frac {t ^ k ln (t)} {t ^ n + 1} : dt & = lim_ {k rightarrow 0+} left[frac{1}{n^2} Bleft(1 – frac{k + 1}{n}, frac{k + 1}{n}right)left[psi^{(0)}left(frac{k + 1}{n} right) – psi^{(0)}left(1 – frac{k + 1}{n} right)right] Law]\
int_0 ^ infty frac { ln (t)} {t ^ n + 1} : dt & = frac {1} {n ^ 2} B left (1 – frac {1} {n} , frac {1} {n} right) left[psi^{(0)}left(frac{1}{n} right) – psi^{(0)}left(1 – frac{1}{n} right)right] \
& = – frac { pi ^ 2} {n ^ 2} operatorname {cosec} left ( frac { pi} {n} right) cot left ( frac { pi} {n} Law)
end {align}

Which is our expression for $ I_n $, The same approach, but twice in relation to $ k $ We come to our expression for $ J_n $:

begin {equation}
J_n = int_0 ^ infty frac { ln ^ 2 (t)} {t ^ n + 1} : dt = frac { pi ^ 3} {n ^ 3} operatorname {cosec} left ( frac { pi} {n} right) left[operatorname{cosec}^2left(frac{pi}{n}right) + cot^2left(frac{pi}{n}right) right]
end {equation}

And in fact we can generalize:

begin {equation}
int_0 ^ infty frac { ln ^ p (t)} { left (t ^ n + 1 right) ^ m} : dt = lim_ {k rightarrow 0} frac {d ^ p} {dk ^ p} left[frac{1}{n} Bleft(1 – frac{k + 1}{n}, frac{k + 1}{n}right)right]
end {equation}

From where $ p in mathbb {N} $

However, this method was only an extension of another integral. I'm curious if I had just started $ I_n, J_n $ Which alternative methods could be used?

How do you solve a system of two equations and two variables depending on other terms?

I want to find C1 and C2 in terms of on and e from the following system of equations:

60 + 31 a + 4 a ^ 2 + 4 Cl 2 (4 + a) (873 + 444 a + 56 a ^ 2) e + 128 Cl ^ 2 C2 ^ 2 (3 + a) (4 + a) (9 ) + 2 a) (33 + 8 a) e ^ 2-3072 C1 ^ 3 C2 ^ 3 (4 + a) ^ 2 (9 + 2 a) ^ 3 e ^ 3 == 0

60 + 31 a + 4 a ^ 2 + C1 C2 (4 + a) (3267 + 8 a (207 + 26 a)) e + 16 C1 ^ 2 C2 ^ 2 (4 + a) (9 + 2 a) ( 837 + 468 a + 64 a ^ 2) e ^ 2 - 4 C1 ^ 3 C2 ^ 3 (4 + a) (9 + 2a) ^ 2 (18333 + 8472 a + 976 a ^ 2) e ^ 3 == 0

If I used "solve,"

To solve[{60 + 31 a + 4 a^2 + 4 C1 C2 (4 + a) (873 + 444 a + 56 a^2) e + 
128 C1^2 C2^2 (3 + a) (4 + a) (9 + 2 a) (33 + 8 a) e^2 - 
3072 C1^3 C2^3 (4 + a)^2 (9 + 2 a)^3 e^3 == 0, 60 + 31 a + 4 a^2 + C1 C2 (4 + a) (3267 + 8 a (207 + 26 a)) e + 16 C1^2 C2^2 (4 + a) (9 + 2 a) (837 + 468 a + 64 a^2) e^2 - 4 C1^3 C2^3 (4 + a) (9 + 2 a)^2 (18333 + 8472 a + 976 a^2) e^3 == 0}, {C1, C2}]

I have: {}

Thanks for helping!!!

Differential Equations – Solve the PDE with spherical harmonics with DSolve

I'm trying to solve the spherical harmonics in Mathemtica. My code is:

pde = 1 / Sin[[Theta]]^ 2 D[f[f[f[f[[Theta], [Phi]]{{[Phi], 2}]+
cot[[Theta]]D[f[f[f[f[[Theta], [Phi]], [Theta]]+
D[f[f[f[f[[Theta], [Phi]]{{[Theta], 2}]+ c f[[Theta], [Phi]]== 0

DSolve[pdef[pdef[pdef[pdef[[Theta], [Phi]]{{[Theta], [Phi]}]

DSolve does not seem to be able to solve this PDE. Am I making a mistake somewhere here?

postgresql – How to solve FATAL: no entry "pg_hba.conf" for host "192.168.1.68", user "postgres", database "symphonydb", SSL disabled

My company has 2 Ubuntu servers (Ver 18)
svr-erpdb (IP: 192.168.2.1/24 & GW: 192.168.2.254)
svr-erapp (IP: 192.168.2 / 2/24 & GW: 192.168.2.254)
url 192.168.2.2 for accessing erp.

Now we set up 2 vm for over 2 erp servers in DR Center.
However, the IP segment of the DR center is 192.168.1.0 / 24

I had done below:

Step 1: Change both server IP addresses
svr-erpdb changes to 192.168.1.67/24 & Gw: 192.168.1.222
svr-erpapp switches to 192.168.1.68/24 & Gw: 192.168.1.222
Result: Can ping both servers from the client PC

Step 2: Update pg_hba.conf to svr-erpdb
change to 192.168.1.68 from 192.168.2.2

Ori pg_hba.conf

Pg_hba.conf has been updated

then sudo restart both servers

Step 3: Update postgresql.conf
Change IP from 192.168.2.1.192.168.2.1 to 192.168.1.67.192.168.1.68

Ori postgresql.conf

Postgresql.conf updated

then reboot sudo

Step 4: Change the URL to a new IP address
192.168.1.68

Yellow error page appears said: FATAL: no pg_hba.conf entry for host "192.168.1.68", user "postgres", database "symphonydb", SSL off

error page

Pls help to solve this problem.

Many Thanks .