forms – scenario for validation in two transmission times (the second validates and shows a previous hidden field)

I use alter_form to & # 39; user_login_form & # 39; to change. The problem is that I am hiding a field and I want to show it to the user and validate it ONLY AFTER login and passport are validated (The user previously clicked the "Login" button.)

How can I tell the form that I am not done yet and have to fill in a new field that can now be viewed and validated?

I'm not sure which approach is the best? Did someone have the same situation before

SharePoint 2010 with REPLACE and FIND functions is executed several times in a calculated field

I am working on a SharePoint 2010 website with a field that contains three letters separated by a hyphen e.g. AMO-SMF.

I have created an invoice that can do that FIND and REPLACE However, there are seven different three-letter abbreviations, which I have to replace with a name. These are as follows:

=IF(ISERROR(FIND("AMO",Result)),Result,REPLACE(Result,FIND("AMO",Result),3,"Amosite"))

    =IF(ISERROR(FIND("CRO",Result)),Result,REPLACE(Result,FIND("CRO",Result),3,"Crocidolite"))

    =IF(ISERROR(FIND("CHR",Result)),Result,REPLACE(Result,FIND("CHR",Result),3,"Chrysotile"))

    =IF(ISERROR(FIND("UMF",Result)),Result,REPLACE(Result,FIND("UMF",Result),3,"Unknown Mineral Fibre"))

    =IF(ISERROR(FIND("ORG",Result)),Result,REPLACE(Result,FIND("ORG",Result),3,"Organic Fibre Type"))

    =IF(ISERROR(FIND("SMF",Result)),Result,REPLACE(Result,FIND("SMF",Result),3,"Organic Fibre Type"))

    =IF(ISERROR(FIND("NFD",Result)),Result,REPLACE(Result,FIND("NFD",Result),3,"No Fibres Detected"))

Is it possible to loop in SharePoint 2010 calculated fields that covers all of these instances?

Precise measurement of the execution times of ASP.NET Core 3.x actions (web API project)?

I want to be able to log the time spent by a particular web API action in an ASP.NET Core 3.x application.

This is a very old ASP.NET question based on global action filters, but in ASP.NET Core I think middlewares are more appropriate.

From a customer perspective, I want to measure the following time as accurately as possible:

Time to first byte - Time spent to send the request

So I implemented the following with a slightly modified code from c-sharpcorner:

/// 
/// tries to measure request processing time
/// 
public class ResponseTimeMiddleware
{
    // Name of the Response Header, Custom Headers starts with "X-"  
    private const string ResponseHeaderResponseTime = "X-Response-Time-ms";

    // Handle to the next Middleware in the pipeline  
    private readonly RequestDelegate _next;

    ///
    public ResponseTimeMiddleware(RequestDelegate next)
    {
        _next = next;
    }

    ///
    public Task InvokeAsync(HttpContext context)
    {
        // skipping measurement of non-actual work like OPTIONS
        if (context.Request.Method == "OPTIONS")
            return _next(context);

        // Start the Timer using Stopwatch  
        var watch = new Stopwatch();
        watch.Start();

        context.Response.OnStarting(() => {
            // Stop the timer information and calculate the time   
            watch.Stop();
            var responseTimeForCompleteRequest = watch.ElapsedMilliseconds;
            // Add the Response time information in the Response headers.   
            context.Response.Headers(ResponseHeaderResponseTime) = responseTimeForCompleteRequest.ToString();

            var logger = context.RequestServices.GetService();
            string fullUrl = $"{context.Request.Scheme}://{context.Request.Host}{context.Request.Path}{context.Request.QueryString}";
            logger?.LogDebug($"(Performance) Request to {fullUrl} took {responseTimeForCompleteRequest} ms");

            return Task.CompletedTask;
        });

        // Call the next delegate/middleware in the pipeline   
        return _next(context);
    }
}

Startup.cs (insert middleware)

public void Configure(IApplicationBuilder app, IWebHostEnvironment env, ILoggerFactory loggerFactory,
    ILoggingService logger, IHostApplicationLifetime lifetime, IServiceProvider serviceProvider)
{
    app.UseResponseCaching();

    app.UseMiddleware();

    // ...
}

Is that a good approach? I am mainly interested in accuracy and do not waste server resources.

Java – fight for the AI ​​to repeat itself an infinite number of times

I follow this as a guideline to find simple AI for an enemy since I'm new to Java.

https://www.javacodegeeks.com/2014/08/game-ai-an-introduction-to-behaviour-trees.html

https://github.com/obviam/behavior-trees/tree/master/src/net/obviam/bt

I call this function:

AI goombaBrain = Routines.selector(Routines.repeatInfinite(Routines.wander(Board.board, InitObject.goomba)));

InitObject.goomba.setRoutine(goombaBrain);

However, once it has moved to a random location, it will not automatically reset. Any ideas? If you need more information, please let me know. (InitObject.goomba is the enemy)

Ag.algebraic geometry – characteristic polynomial of a symmetrical $ 8 times 8 $ matrix with indefinite entries in relation to octonionic multiplication

I look at $ 1, i, j, k, l, m, n, o $ the standard base of the (complexed at will) octon ions ($ mathbb {O} $ for the octon ions).
To let $ a = x_1.1 + ldots + x_8.o $. $ b = x_9.1 + ldots + x_ {16} .o $ and $ c = x_ {17} .1+ ldots + x_ {24} .o $, Where $ x_1, ldots, x_ {24} $ are indefinite about the basic field (pron $ mathbb {C} $).

I denote by $ L_a $ the $ 8 times $ 8 Matrix that represents the left multiplication with $ a $ in the $ mathbb {O} simeq mathbb {C} ^ 8 $ and $ R_a $ the $ 8 times $ 8 Matrix that represents the correct multiplication with $ a $, Similar names for $ b $ and $ c $, I want to calculate the characteristic polynomial of the symmetric matrix:
$$ S = R_a L_b L_c + {} ^ {t} (R_a L_b L_c), $$
Where $ {} ^ {t} X $ is the transpose of $ X $,

I tried Macaulay2 and this calculation seems to go far beyond what my computer (which is supposed to be a fairly powerful portable workstation) offers.

A simple reformulation of the eigenvalue problem on a well-chosen basis (namely let $ mathbb {H} $ be the quaternionic subalgebra of $ b $ and $ c $, Splits $ mathbb {O} $ how $ mathbb {H} bigoplus mathbb {H} .e $, Where $ e $ is orthogonal to $ mathbb {H} $ and take a base adapted to this decomposition) shows that:
$$ (T – mathrm {Re} (( overline {b} c) overline {a})) ^ 4 textrm {divides} det (S-T.id), $$
Where $ mathrm {Re} (z) $ is the real part of $ z in mathbb {O} $,

I put $ f (T) = dfrac {det (S-Tid)} {(T – mathrm {Re} ((bc) overline {a}) ^ 4} $, A variety of calculations over finite fields and specialization of the $ x_i $ random values ​​suggests that $ f (T) $ is indeed a square, we say $ f (T) = g (T) ^ 2 $, Where $ g $ is a quadratic polynomial in $ T $,

I would like a closed expression of $ g (T) $, May it be a clean formula $ a, b $ and $ c $ or a dirty "in coordinates" polynomial. I would be very happy about any suggestion. I would also be interested in a theoretical argument that shows that $ f (T) $ is indeed a square.

Many thanks!

Why are assets (images) reported as 28 times larger in Unity Build?

I am trying to reduce a Unity WebGL build size that is currently 30 MB for the data asset. I installed the Build Report Inspector. When you click the Source Assets tab and select Size, the top entries are displayed as images. Fine. However, all sizes listed were between 4 times and 30 times the size of the file on the hard disk. Is this just a build reporter bug / artifact or a real issue I need to address to reduce build sizes?

  • To edit *
    Interestingly, one of the files is a text file, and the size specified by the Unity Build report is the same as that on disk …?

Large image sizes in the build report

How many times can a number guide an elliptic curve?

There are several upper bounds on the number of elliptic curves (e.g. over Q) to isomorphism with a given ladder N. Probably the best of Helfgott-Venkatesh of order N ^ {0.22} is given (or it may be an improvement) possible) knowledge of improved limits for 3 torsions in class groups).

My question is whether there is a lower limit? I don't know how much of this question makes sense because it feels like the most possible candidate for conducting is not a conductor. Is there a similar result?

If the Republicans stop lying, is that the end of the party? How many times can they lie to cover up a lie and how often will the Cons?

You mean like tomorrow?

"Trump just thought people would celebrate and that would end the entire impeachment interview. Any follow-up questions?"

Yes, no … tomorrow is not good.

Don Wilson and Stephen King are offering $ 200,000 to charity when the White House holds its first press conference after 300 days:

https://www.theguardian.com/books/2020/jan/10/don -…