universal 0-dimensional separable metric subspaces

To let $ mathscr U: = (U delta) $ let be a separable metric space that is universal for all finite metric spaces, d. H. for every finite metric space $ mathscr X: = (X d) $ There
exists an isometric embedding of $ mathscr X $ in
$ \ mathscr U. $

Q: Is there a 0-dimensional subset?
$ C subset U $ in the $ mathscr U $ so that room
$ (C , \ delta | C ! Times ! C) $ is universal for all finite metric spaces?

The same applies to question

As long as I know, these are questions to open,

What code do I need to embed in my website for cross-domain Google Analytics (Universal Analytics)?

I have a website that's on multiple domains, and I want to track it universally. Currently, I do not care about statistics per domain, I just want to see the total page views.
I am also not interested in links between domains – they could be counted as two sessions.

So I've created a new property in the https: //analytics.google.com dashboard, but I need to enter a "default URL" (where I've only selected one of my domains). Then I found the tracking code that starts with ,

I then used the tag manager to get information about universal tracking: https://support.google.com/tagmanager/answer/6164469. That's why I created a Google Analytics: Universal Analytics tag with a variable with Google's tracking ID. Analytics property and with Cross-domain tracking configured with all my domain names (separated by a comma).
The Tag Manager has a button in the title bar that looks like this: "GTM -…" – It will pop up a popup window titled "Install Google Tag Manager" with a code I put into it Embed Head Tag: and code to embed in the body tag: ,

Do I just need to embed the ones? GTAG Code? only the Google Tag Manager Code? Or both?

Thank you very much

How do I manually set a field in Universal Analytics?

In a given situation, some field data for Analytics must be set manually. In my JS I have the following:

ga(function(tracker) {
   tracker.set('campaignKeyword', 'my keyword');
   tracker.send('event');
});

In Analytics, however, nothing seems to come through.

I ran console.log(tracker) and it's a valid Universal Analytics tracking object. I'm just not sure what I'm doing wrong. I referenced this documentation.

What do I miss?

Universal Property – Why should I invest Microtek Greenburg in a nature inspired residential paradise?

The observation of lush greenery makes the city residents quite nostalgic. But if you choose to make Microtek Greenburg your home, nostalgia is a thing of the past. Witness a dazzling sunrise and mesmerizing sunset, breathe fresh air and live your dream life while you're part of the Microtek Greenburg community.

Ready to move The Microtek Greenburg project can achieve good results in terms of connectivity. It is close to the IGI Airport, the NH-8, the Northern Peripheral Road, the Kundli-Manesar Palwal Expressway and a planned subway station. The proximity to a multi-purpose corridor on the Manesar Industrial Base further enhances the attractiveness of this residential project. The proposed 100-acre golf course and up-and-coming modern school are enough to inspire the imagination of potential home buyers.

Microtek Greenburg Sector 86 Gurgaon is immensely proud to be working with a highly esteemed construction company called L & T. Taking into account the same fact; One can rely on the quality of the construction, which is further enhanced by features such as earthquake-resistant structure and negligible possibilities of errors such as leaks. This Vasstu-compliant housing project has a diverse range of basic equipment. There is also a multi-cuisine restaurant where you can enjoy delicious dishes.

In addition, it offers yoga & aerobics, swimming pool, clubhouse, basketball court, meditation court, health club and gymnasium. Rainwater harvesting is certainly one of the outstanding features of the Ready to Move Microtek Greenburg project. An experienced broker like Orion could provide the necessary support for providing all the information related to this project.

Ag.algebraische Geometrie – Understand the universal sheaf on site

Suppose I have a projective, flat morphism $ pi: X to S $ between smooth projective varieties over $ mathbb {C} $, Through the work of Simpson exists a module space $ M = M (X / S, v) $ of torsion – free (semi – stable) coherent slices deposited on the fibers of $ pi $ with fixed discrete data $ v $, So the sheaves are on twist $ X $provided $ S $ is not a point, but torsion free on the fibers.

I would like to assume that this module space is actually fineSo there is a universal sheaf $ mathcal {F} $ on $ X times_ {S} M $ that is torsion free. One of the most important features is that for everyone $ m in M ​​$. $ F_ {m} = mathcal {F} | _ {X times_ {S} {m}} $ is the sheaf that represents the point $ m in M ​​$, Basically, I try to understand $ mathcal {F} $ locally:

(1) On my first question, I assume $ P = (x, m) in X times_ {S} M $ is such that $ m $ represents a locally free sheaf on the fibers of $ pi $, Will the stalk $ mathcal {F} _ {P} $ be a free one $ mathcal {O} _ {X times_ {S} M, P} $-Module? In words, should universal handle stems be free modules over the local rings at points that represent locally free sheaves?

(2) I think my second question is closely related. Due to the universal property, I think it is right for $ P = (x, m) $ We have the isomorphism $ mathcal {F} _ {P} cong (F_ {m}) _ {x} $, But I am confused as to how this isomorphism is given. Suppose the local ring of $ X times_ {S} M $ at the $ P $ is

$$ A = mathbb {C} ((x, y, w, z)) / (xy-wz) $$

from where $ (x, y) $ are coordinates on $ X $ and $ (w, z) $ are coordinates on $ M $, So $ mathcal {F} _ {P} $ should be one $ A $Module while $ (F_ {m}) _ {x} $ should be one $ mathbb {C} ((x, y)) / (xy) $-Module. How is the isomorphism given?
What happens to that $ w, z $ Variables, if this identification is made?

Reference Request – A Universal Algebra Survey

I searched for a good list for Univesal Algebra because I could get the best possible list for each post from each site, and then decided to create it.

For this I would like to make suggestions for books in three forms, introductory books in universal algebra, advanced books in universal algebra, books in model theory, but there are enough universal algebra on this list, lecture scripts in universal algebra or lecture notes in Model Theory that contain some topics in Universal Algebra.
A small description of the book will also be a big thank you, and if you've actually read the book, a small review would be great.

The idea is to leave the post so that new books can always be added to the list.

Geometric Topology – A Universal Node Chain?

To let $ P $ be a simple (not self-cutting) infinite polygonal chain
in the $ mathbb {R} ^ 3 $. $ P = (v_0, v_1, v_2, ldots) $,
Accept that $ P $ is that the segment $ v_0 v_i $ does not cut $ P $
(except at the endpoints) for all $ i $,
To let $ K_i $ be the (stick) knot formed by joining $ v_0 $ to $ v_i $ and
ignore the rest of it $ P $ Furthermore $ v_i $,

Q1, Are there any $ P $ so that all different node types are realized
from a few $ K_i $?

Note that when we define $ K_ {ij} $ as the cycle $ (v_i, ldots, v_j) $, then that is
Answer is trivial Yesby simply lining up each node type individually,
connected by a corresponding gap, and choose $ i $ and $ j $ span the next node.

I ask for a kind of universal chain $ P $,
It is okay if nodes are realized multiple times ($ K_ {i_1} sim K_ {i_2} $)
But I do not want to miss a knot type.

I do not think the discretization to knot is important, but if so,
change $ P $ to a curve in $ mathbb {R} ^ 3 $ and $ K_i $ connect with everyone
$ p_i in P $,

Q2, If the answer to Q1 is Nocan some interesting
Subset of all nodes are realized in a similar way by some $ P $?

How much solution to fill Paterson Universal Tank during film development?

Moving with Paterson tanks is done by rotating the roller, so only the film needs to be covered. For other systems where stirring may be by inversion or otherwise, the tank must be present nearly full (some air is needed).

The necessary chemical reactions are concentration- and time-dependent. More or less solution in the tank does not affect the results, as long as the film is sufficiently covered.