Assume $x≥0$. Find smallest $N$ such that $x/2^Nin[0,1]$

I want to write a while loop which gives me the smallest $N$ such that $x/2^N$ is in the interval $[0,1]$

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# Tag: x2Nin01

## Find smallest $N$ such that $x/2^Nin[0,1]$ (in python)

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Assume $x≥0$. Find smallest $N$ such that $x/2^Nin[0,1]$

I want to write a while loop which gives me the smallest $N$ such that $x/2^N$ is in the interval $[0,1]$

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